Asosiy tarkibga oʻtish
Baholash
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p ga nisbatan hosilani topish
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Veb-qidiruvdagi o'xshash muammolar

Baham ko'rish

\frac{5^{5}p^{7}}{25^{1}p^{3}}
Ifodani qisqartirish uchun eksponent qoidalaridan foydalanish.
\frac{5^{5}p^{7-3}}{25^{1}}
Ayni asosning daraja ko'rsatkichi bo'lish uchun maxrajning darajasini surat darajasidan bo'ling.
\frac{5^{5}p^{4}}{25^{1}}
7 dan 3 ni ayirish.
\frac{3125p^{4}}{25^{1}}
5 ni 5 daraja ko'rsatgichiga oshirish.
125p^{4}
3125 ni 25 ga bo'lish.
\frac{\mathrm{d}}{\mathrm{d}p}(\frac{5^{5}p^{4}}{25})
Surat va maxrajdagi ikkala p^{3} ni qisqartiring.
\frac{\mathrm{d}}{\mathrm{d}p}(\frac{3125p^{4}}{25})
5 daraja ko‘rsatkichini 5 ga hisoblang va 3125 ni qiymatni oling.
\frac{\mathrm{d}}{\mathrm{d}p}(125p^{4})
125p^{4} ni olish uchun 3125p^{4} ni 25 ga bo‘ling.
4\times 125p^{4-1}
ax^{n} hosilasi – nax^{n-1}.
500p^{4-1}
4 ni 125 marotabaga ko'paytirish.
500p^{3}
4 dan 1 ni ayirish.