(4v^2-5v+3)+(-v^2+6v+7) eching

$$( 4 v ^ { 2 } - 5 v + 3 ) + ( - v ^ { 2 } + 6 v + 7 )$$

Baholash

$$3v^{2}+v+10$$

Yechim qadamlari

v ni olish uchun -5v va 6v ni birlashtirish.

$$4v^{2}+v+3-v^{2}+7$$

10 olish uchun 3 va 7'ni qo'shing.

$$4v^{2}+v+10-v^{2}$$

3v^{2} ni olish uchun 4v^{2} va -v^{2} ni birlashtirish.

$$3v^{2}+v+10$$

v ga nisbatan hosilani topish

$$6v+1$$

Yig'indi uchun derivativ qoidasidan foydalanish qadamlari

v ni olish uchun -5v va 6v ni birlashtirish.

$$\frac{\mathrm{d}}{\mathrm{d}v}(4v^{2}+v+3-v^{2}+7)$$

10 olish uchun 3 va 7'ni qo'shing.

$$\frac{\mathrm{d}}{\mathrm{d}v}(4v^{2}+v+10-v^{2})$$

3v^{2} ni olish uchun 4v^{2} va -v^{2} ni birlashtirish.

$$\frac{\mathrm{d}}{\mathrm{d}v}(3v^{2}+v+10)$$

Polinomialning hosilasi bu uning shartlari hosilasining yig‘indisiga teng. Konstant shartning hosilasi 0. ax^{n} ning hosilasi nax^{n-1}.

$$2\times 3v^{2-1}+v^{1-1}$$

2 ni 3 marotabaga ko'paytirish.

$$6v^{2-1}+v^{1-1}$$

2 dan 1 ni ayirish.

$$6v^{1}+v^{1-1}$$

1 dan 1 ni ayirish.

$$6v^{1}+v^{0}$$

Har qanday t sharti uchun t^{1}=t.

$$6v+v^{0}$$

Har qanday t sharti uchun (0 bundan mustasno) t^{0}=1.

$$6v+1$$