(4)(x^2-3)*(x+1)-(x^2+5)*(x-2) eching

$$( 4 ) ( x ^ { 2 } - 3 ) \cdot ( x + 1 ) - ( x ^ { 2 } + 5 ) \cdot ( x - 2 )$$

Baholash

$$3x^{3}+6x^{2}-17x-2$$

Yechim qadamlari

4 ga x^{2}-3 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$\left(4x^{2}-12\right)\left(x+1\right)-\left(x^{2}+5\right)\left(x-2\right)$$

4x^{2}-12 ga x+1 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$4x^{3}+4x^{2}-12x-12-\left(x^{2}+5\right)\left(x-2\right)$$

x^{2}+5 ga x-2 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$4x^{3}+4x^{2}-12x-12-\left(x^{3}-2x^{2}+5x-10\right)$$

x^{3}-2x^{2}+5x-10 teskarisini topish uchun har birining teskarisini toping.

$$4x^{3}+4x^{2}-12x-12-x^{3}+2x^{2}-5x+10$$

3x^{3} ni olish uchun 4x^{3} va -x^{3} ni birlashtirish.

$$3x^{3}+4x^{2}-12x-12+2x^{2}-5x+10$$

6x^{2} ni olish uchun 4x^{2} va 2x^{2} ni birlashtirish.

$$3x^{3}+6x^{2}-12x-12-5x+10$$

-17x ni olish uchun -12x va -5x ni birlashtirish.

$$3x^{3}+6x^{2}-17x-12+10$$

-2 olish uchun -12 va 10'ni qo'shing.

$$3x^{3}+6x^{2}-17x-2$$

Kengaytirish

$$3x^{3}+6x^{2}-17x-2$$

Yechim qadamlari

4 ga x^{2}-3 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$\left(4x^{2}-12\right)\left(x+1\right)-\left(x^{2}+5\right)\left(x-2\right)$$

4x^{2}-12 ga x+1 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$4x^{3}+4x^{2}-12x-12-\left(x^{2}+5\right)\left(x-2\right)$$

x^{2}+5 ga x-2 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$4x^{3}+4x^{2}-12x-12-\left(x^{3}-2x^{2}+5x-10\right)$$

x^{3}-2x^{2}+5x-10 teskarisini topish uchun har birining teskarisini toping.

$$4x^{3}+4x^{2}-12x-12-x^{3}+2x^{2}-5x+10$$

3x^{3} ni olish uchun 4x^{3} va -x^{3} ni birlashtirish.

$$3x^{3}+4x^{2}-12x-12+2x^{2}-5x+10$$

6x^{2} ni olish uchun 4x^{2} va 2x^{2} ni birlashtirish.

$$3x^{3}+6x^{2}-12x-12-5x+10$$

-17x ni olish uchun -12x va -5x ni birlashtirish.

$$3x^{3}+6x^{2}-17x-12+10$$

-2 olish uchun -12 va 10'ni qo'shing.

$$3x^{3}+6x^{2}-17x-2$$