(4+5)^2+(7div7)^5-(10+80div40) eching

$$( 4 + 5 ) ^ { 2 } + ( 7 \div 7 ) ^ { 5 } - ( 10 + 80 \div 40 )$$

Baholash

$$70$$

Yechim qadamlari

1 ni olish uchun 7 ni 7 ga bo‘ling.

$$\left(4+5\right)^{2}+1^{5}-\left(10+\frac{80}{40}\right)$$

9 olish uchun 4 va 5'ni qo'shing.

$$9^{2}+1^{5}-\left(10+\frac{80}{40}\right)$$

2 daraja ko‘rsatkichini 9 ga hisoblang va 81 ni qiymatni oling.

$$81+1^{5}-\left(10+\frac{80}{40}\right)$$

5 daraja ko‘rsatkichini 1 ga hisoblang va 1 ni qiymatni oling.

$$81+1-\left(10+\frac{80}{40}\right)$$

82 olish uchun 81 va 1'ni qo'shing.

$$82-\left(10+\frac{80}{40}\right)$$

2 ni olish uchun 80 ni 40 ga bo‘ling.

$$82-\left(10+2\right)$$

12 olish uchun 10 va 2'ni qo'shing.

$$82-12$$

70 olish uchun 82 dan 12 ni ayirish.

$$70$$

Omil

$$2\times 5\times 7$$