(32*25)*(10^-10*10^-11) eching

$$( 32 \times 25 ) \times ( 10 ^ { - 10 } \times 10 ^ { - 11 } )$$

Baholash

$$\frac{1}{1250000000000000000}=8 \cdot 10^{-19}$$

Yechim qadamlari

Ayni asosning daraja ko‘rsatkichlarini ko‘paytirish uchun ularning darajalarini qo‘shing. -10 va -11 ni qo‘shib, -21 ni oling.

$$32\times 25\times 10^{-21}$$

800 hosil qilish uchun 32 va 25 ni ko'paytirish.

$$800\times 10^{-21}$$

-21 daraja ko‘rsatkichini 10 ga hisoblang va \frac{1}{1000000000000000000000} ni qiymatni oling.

$$800\times \frac{1}{1000000000000000000000}$$

\frac{1}{1250000000000000000} hosil qilish uchun 800 va \frac{1}{1000000000000000000000} ni ko'paytirish.

$$\frac{1}{1250000000000000000}$$

Omil

$$\frac{1}{2 ^ {16} \cdot 5 ^ {19}} = 8 \times 10^{-19}$$