(3a^{2}-b^{2})^2-(a^2-3b^2)^2 eching

$$( 3 a ^ { 2 } - b ^ { 2 } ) ^ { 2 } - ( a ^ { 2 } - 3 b ^ { 2 } ) ^ { 2 }$$

Baholash

$$8\left(a^{4}-b^{4}\right)$$

Yechim qadamlari

\left(p-q\right)^{2}=p^{2}-2pq+q^{2} binom teoremasini \left(3a^{2}-b^{2}\right)^{2} kengaytirilishi uchun ishlating.

$$9\left(a^{2}\right)^{2}-6a^{2}b^{2}+\left(b^{2}\right)^{2}-\left(a^{2}-3b^{2}\right)^{2}$$

Daraja ko‘rsatkichini boshqa ko‘rsatkichga oshirish uchun, darajalarini ko‘paytiring. 2 va 2 ni ko‘paytirib, 4 ni oling.

$$9a^{4}-6a^{2}b^{2}+\left(b^{2}\right)^{2}-\left(a^{2}-3b^{2}\right)^{2}$$

Daraja ko‘rsatkichini boshqa ko‘rsatkichga oshirish uchun, darajalarini ko‘paytiring. 2 va 2 ni ko‘paytirib, 4 ni oling.

$$9a^{4}-6a^{2}b^{2}+b^{4}-\left(a^{2}-3b^{2}\right)^{2}$$

\left(p-q\right)^{2}=p^{2}-2pq+q^{2} binom teoremasini \left(a^{2}-3b^{2}\right)^{2} kengaytirilishi uchun ishlating.

$$9a^{4}-6a^{2}b^{2}+b^{4}-\left(\left(a^{2}\right)^{2}-6a^{2}b^{2}+9\left(b^{2}\right)^{2}\right)$$

Daraja ko‘rsatkichini boshqa ko‘rsatkichga oshirish uchun, darajalarini ko‘paytiring. 2 va 2 ni ko‘paytirib, 4 ni oling.

$$9a^{4}-6a^{2}b^{2}+b^{4}-\left(a^{4}-6a^{2}b^{2}+9\left(b^{2}\right)^{2}\right)$$

Daraja ko‘rsatkichini boshqa ko‘rsatkichga oshirish uchun, darajalarini ko‘paytiring. 2 va 2 ni ko‘paytirib, 4 ni oling.

$$9a^{4}-6a^{2}b^{2}+b^{4}-\left(a^{4}-6a^{2}b^{2}+9b^{4}\right)$$

a^{4}-6a^{2}b^{2}+9b^{4} teskarisini topish uchun har birining teskarisini toping.

$$9a^{4}-6a^{2}b^{2}+b^{4}-a^{4}+6a^{2}b^{2}-9b^{4}$$

8a^{4} ni olish uchun 9a^{4} va -a^{4} ni birlashtirish.

$$8a^{4}-6a^{2}b^{2}+b^{4}+6a^{2}b^{2}-9b^{4}$$

0 ni olish uchun -6a^{2}b^{2} va 6a^{2}b^{2} ni birlashtirish.

$$8a^{4}+b^{4}-9b^{4}$$

-8b^{4} ni olish uchun b^{4} va -9b^{4} ni birlashtirish.

$$8a^{4}-8b^{4}$$

Kengaytirish

$$8a^{4}-8b^{4}$$

Yechim qadamlari

\left(p-q\right)^{2}=p^{2}-2pq+q^{2} binom teoremasini \left(3a^{2}-b^{2}\right)^{2} kengaytirilishi uchun ishlating.

$$9\left(a^{2}\right)^{2}-6a^{2}b^{2}+\left(b^{2}\right)^{2}-\left(a^{2}-3b^{2}\right)^{2}$$

Daraja ko‘rsatkichini boshqa ko‘rsatkichga oshirish uchun, darajalarini ko‘paytiring. 2 va 2 ni ko‘paytirib, 4 ni oling.

$$9a^{4}-6a^{2}b^{2}+\left(b^{2}\right)^{2}-\left(a^{2}-3b^{2}\right)^{2}$$

Daraja ko‘rsatkichini boshqa ko‘rsatkichga oshirish uchun, darajalarini ko‘paytiring. 2 va 2 ni ko‘paytirib, 4 ni oling.

$$9a^{4}-6a^{2}b^{2}+b^{4}-\left(a^{2}-3b^{2}\right)^{2}$$

\left(p-q\right)^{2}=p^{2}-2pq+q^{2} binom teoremasini \left(a^{2}-3b^{2}\right)^{2} kengaytirilishi uchun ishlating.

$$9a^{4}-6a^{2}b^{2}+b^{4}-\left(\left(a^{2}\right)^{2}-6a^{2}b^{2}+9\left(b^{2}\right)^{2}\right)$$

Daraja ko‘rsatkichini boshqa ko‘rsatkichga oshirish uchun, darajalarini ko‘paytiring. 2 va 2 ni ko‘paytirib, 4 ni oling.

$$9a^{4}-6a^{2}b^{2}+b^{4}-\left(a^{4}-6a^{2}b^{2}+9\left(b^{2}\right)^{2}\right)$$

Daraja ko‘rsatkichini boshqa ko‘rsatkichga oshirish uchun, darajalarini ko‘paytiring. 2 va 2 ni ko‘paytirib, 4 ni oling.

$$9a^{4}-6a^{2}b^{2}+b^{4}-\left(a^{4}-6a^{2}b^{2}+9b^{4}\right)$$

a^{4}-6a^{2}b^{2}+9b^{4} teskarisini topish uchun har birining teskarisini toping.

$$9a^{4}-6a^{2}b^{2}+b^{4}-a^{4}+6a^{2}b^{2}-9b^{4}$$

8a^{4} ni olish uchun 9a^{4} va -a^{4} ni birlashtirish.

$$8a^{4}-6a^{2}b^{2}+b^{4}+6a^{2}b^{2}-9b^{4}$$

0 ni olish uchun -6a^{2}b^{2} va 6a^{2}b^{2} ni birlashtirish.

$$8a^{4}+b^{4}-9b^{4}$$

-8b^{4} ni olish uchun b^{4} va -9b^{4} ni birlashtirish.

$$8a^{4}-8b^{4}$$