(3^2+5^0)div5-(-9+7)^3+sqrt{(-5)^2+22div2}= eching

$$( 3 ^ { 2 } + 5 ^ { 0 } ) \div 5 - ( - 9 + 7 ) ^ { 3 } + \sqrt { ( - 5 ) ^ { 2 } + 22 \div 2 } =$$

Baholash

$$16$$

Yechim qadamlari

2 daraja ko‘rsatkichini 3 ga hisoblang va 9 ni qiymatni oling.

$$\frac{9+5^{0}}{5}-\left(-9+7\right)^{3}+\sqrt{\left(-5\right)^{2}+\frac{22}{2}}$$

0 daraja ko‘rsatkichini 5 ga hisoblang va 1 ni qiymatni oling.

$$\frac{9+1}{5}-\left(-9+7\right)^{3}+\sqrt{\left(-5\right)^{2}+\frac{22}{2}}$$

10 olish uchun 9 va 1'ni qo'shing.

$$\frac{10}{5}-\left(-9+7\right)^{3}+\sqrt{\left(-5\right)^{2}+\frac{22}{2}}$$

2 ni olish uchun 10 ni 5 ga bo‘ling.

$$2-\left(-9+7\right)^{3}+\sqrt{\left(-5\right)^{2}+\frac{22}{2}}$$

-2 olish uchun -9 va 7'ni qo'shing.

$$2-\left(-2\right)^{3}+\sqrt{\left(-5\right)^{2}+\frac{22}{2}}$$

3 daraja ko‘rsatkichini -2 ga hisoblang va -8 ni qiymatni oling.

$$2-\left(-8\right)+\sqrt{\left(-5\right)^{2}+\frac{22}{2}}$$

-8 ning teskarisi 8 ga teng.

$$2+8+\sqrt{\left(-5\right)^{2}+\frac{22}{2}}$$

10 olish uchun 2 va 8'ni qo'shing.

$$10+\sqrt{\left(-5\right)^{2}+\frac{22}{2}}$$

2 daraja ko‘rsatkichini -5 ga hisoblang va 25 ni qiymatni oling.

$$10+\sqrt{25+\frac{22}{2}}$$

11 ni olish uchun 22 ni 2 ga bo‘ling.

$$10+\sqrt{25+11}$$

36 olish uchun 25 va 11'ni qo'shing.

$$10+\sqrt{36}$$

36 ning kvadrat ildizini hisoblab, 6 natijaga ega bo‘ling.

$$10+6$$

16 olish uchun 10 va 6'ni qo'shing.

$$16$$

Omil

$$2^{4}$$