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9+6\sqrt{2}+\left(\sqrt{2}\right)^{2}-4\left(2-\sqrt{2}\right)
\left(a+b\right)^{2}=a^{2}+2ab+b^{2} binom teoremasini \left(3+\sqrt{2}\right)^{2} kengaytirilishi uchun ishlating.
9+6\sqrt{2}+2-4\left(2-\sqrt{2}\right)
\sqrt{2} kvadrati – 2.
11+6\sqrt{2}-4\left(2-\sqrt{2}\right)
11 olish uchun 9 va 2'ni qo'shing.
11+6\sqrt{2}-8+4\sqrt{2}
-4 ga 2-\sqrt{2} ni ko'paytirish orqali distributiv xususiyatdan foydalanish.
3+6\sqrt{2}+4\sqrt{2}
3 olish uchun 11 dan 8 ni ayirish.
3+10\sqrt{2}
10\sqrt{2} ni olish uchun 6\sqrt{2} va 4\sqrt{2} ni birlashtirish.