(24*sqrt{9/16}+12divsqrt[3]{64}-(1/10)^-1)^2 eching

$$( 24 \cdot \sqrt { \frac { 9 } { 16 } } + 12 \div \sqrt[ 3 ] { 64 } - ( \frac { 1 } { 10 } ) ^ { - 1 } ) ^ { 2 }$$

Baholash

$$121$$

Yechim qadamlari

\frac{9}{16} boʻlinmasining kvadrat ildizini \frac{\sqrt{9}}{\sqrt{16}} kvadrat ildizlarining boʻlinmasi sifatida qayta yozing. Surat va maxrajni kvadrat ildizdan chiqaring.

$$\left(24\times \frac{3}{4}+\frac{12}{\sqrt[3]{64}}-\left(\frac{1}{10}\right)^{-1}\right)^{2}$$

18 hosil qilish uchun 24 va \frac{3}{4} ni ko'paytirish.

$$\left(18+\frac{12}{\sqrt[3]{64}}-\left(\frac{1}{10}\right)^{-1}\right)^{2}$$

\sqrt[3]{64} ni hisoblab, 4 natijasiga ega bo‘ling.

$$\left(18+\frac{12}{4}-\left(\frac{1}{10}\right)^{-1}\right)^{2}$$

3 ni olish uchun 12 ni 4 ga bo‘ling.

$$\left(18+3-\left(\frac{1}{10}\right)^{-1}\right)^{2}$$

21 olish uchun 18 va 3'ni qo'shing.

$$\left(21-\left(\frac{1}{10}\right)^{-1}\right)^{2}$$

-1 daraja ko‘rsatkichini \frac{1}{10} ga hisoblang va 10 ni qiymatni oling.

$$\left(21-10\right)^{2}$$

11 olish uchun 21 dan 10 ni ayirish.

$$11^{2}$$

2 daraja ko‘rsatkichini 11 ga hisoblang va 121 ni qiymatni oling.

$$121$$

Omil

$$11^{2}$$