(2x^{3}-y^{3})(2x^3+y^3)(4x^6+y^6) eching

$$( 2 x ^ { 3 } - y ^ { 3 } ) ( 2 x ^ { 3 } + y ^ { 3 } ) ( 4 x ^ { 6 } + y ^ { 6 } )$$

Baholash

$$16x^{12}-y^{12}$$

Yechim qadamlari

2x^{3}-y^{3} ga 2x^{3}+y^{3} ni ko‘paytirish orqali distributiv xususiyatdan foydalaning va ifoda sifatida birlashtiring.

$$\left(4x^{6}-y^{6}\right)\left(4x^{6}+y^{6}\right)$$

Ko‘paytirish qoida yordamida turli kvadratlarga aylantirilishi mumkin: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.

$$\left(4x^{6}\right)^{2}-\left(y^{6}\right)^{2}$$

Daraja ko‘rsatkichini boshqa ko‘rsatkichga oshirish uchun, darajalarini ko‘paytiring. 6 va 2 ni ko‘paytirib, 12 ni oling.

$$\left(4x^{6}\right)^{2}-y^{12}$$

\left(4x^{6}\right)^{2} ni kengaytirish.

$$4^{2}\left(x^{6}\right)^{2}-y^{12}$$

Daraja ko‘rsatkichini boshqa ko‘rsatkichga oshirish uchun, darajalarini ko‘paytiring. 6 va 2 ni ko‘paytirib, 12 ni oling.

$$4^{2}x^{12}-y^{12}$$

2 daraja ko‘rsatkichini 4 ga hisoblang va 16 ni qiymatni oling.

$$16x^{12}-y^{12}$$

Kengaytirish

$$16x^{12}-y^{12}$$

Yechim qadamlari

2x^{3}-y^{3} ga 2x^{3}+y^{3} ni ko‘paytirish orqali distributiv xususiyatdan foydalaning va ifoda sifatida birlashtiring.

$$\left(4x^{6}-y^{6}\right)\left(4x^{6}+y^{6}\right)$$

Ko‘paytirish qoida yordamida turli kvadratlarga aylantirilishi mumkin: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.

$$\left(4x^{6}\right)^{2}-\left(y^{6}\right)^{2}$$

Daraja ko‘rsatkichini boshqa ko‘rsatkichga oshirish uchun, darajalarini ko‘paytiring. 6 va 2 ni ko‘paytirib, 12 ni oling.

$$\left(4x^{6}\right)^{2}-y^{12}$$

\left(4x^{6}\right)^{2} ni kengaytirish.

$$4^{2}\left(x^{6}\right)^{2}-y^{12}$$

Daraja ko‘rsatkichini boshqa ko‘rsatkichga oshirish uchun, darajalarini ko‘paytiring. 6 va 2 ni ko‘paytirib, 12 ni oling.

$$4^{2}x^{12}-y^{12}$$

2 daraja ko‘rsatkichini 4 ga hisoblang va 16 ni qiymatni oling.

$$16x^{12}-y^{12}$$