(2x^2-x+2)(-x-3) eching

$$( 2 x ^ { 2 } - x + 2 ) ( - x - 3 )$$

Baholash

$$-2x^{3}-5x^{2}+x-6$$

Yechim qadamlari

2x^{2}-x+2 ga -x-3 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$2x^{2}\left(-x\right)-6x^{2}-x\left(-x\right)+3x+2\left(-x\right)-6$$

1 hosil qilish uchun -1 va -1 ni ko'paytirish.

$$2x^{2}\left(-x\right)-6x^{2}+xx+3x+2\left(-x\right)-6$$

x^{2} hosil qilish uchun x va x ni ko'paytirish.

$$2x^{2}\left(-x\right)-6x^{2}+x^{2}+3x+2\left(-x\right)-6$$

-5x^{2} ni olish uchun -6x^{2} va x^{2} ni birlashtirish.

$$2x^{2}\left(-x\right)-5x^{2}+3x+2\left(-x\right)-6$$

-2 hosil qilish uchun 2 va -1 ni ko'paytirish.

$$-2x^{2}x-5x^{2}+3x+2\left(-1\right)x-6$$

Ayni asosning daraja ko‘rsatkichlarini ko‘paytirish uchun ularning darajalarini qo‘shing. 2 va 1 ni qo‘shib, 3 ni oling.

$$-2x^{3}-5x^{2}+3x+2\left(-1\right)x-6$$

-2 hosil qilish uchun 2 va -1 ni ko'paytirish.

$$-2x^{3}-5x^{2}+3x-2x-6$$

x ni olish uchun 3x va -2x ni birlashtirish.

$$-2x^{3}-5x^{2}+x-6$$

Kengaytirish

$$-2x^{3}-5x^{2}+x-6$$

Yechim qadamlari

2x^{2}-x+2 ga -x-3 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$2x^{2}\left(-x\right)-6x^{2}-x\left(-x\right)+3x+2\left(-x\right)-6$$

1 hosil qilish uchun -1 va -1 ni ko'paytirish.

$$2x^{2}\left(-x\right)-6x^{2}+xx+3x+2\left(-x\right)-6$$

x^{2} hosil qilish uchun x va x ni ko'paytirish.

$$2x^{2}\left(-x\right)-6x^{2}+x^{2}+3x+2\left(-x\right)-6$$

-5x^{2} ni olish uchun -6x^{2} va x^{2} ni birlashtirish.

$$2x^{2}\left(-x\right)-5x^{2}+3x+2\left(-x\right)-6$$

-2 hosil qilish uchun 2 va -1 ni ko'paytirish.

$$-2x^{2}x-5x^{2}+3x+2\left(-1\right)x-6$$

Ayni asosning daraja ko‘rsatkichlarini ko‘paytirish uchun ularning darajalarini qo‘shing. 2 va 1 ni qo‘shib, 3 ni oling.

$$-2x^{3}-5x^{2}+3x+2\left(-1\right)x-6$$

-2 hosil qilish uchun 2 va -1 ni ko'paytirish.

$$-2x^{3}-5x^{2}+3x-2x-6$$

x ni olish uchun 3x va -2x ni birlashtirish.

$$-2x^{3}-5x^{2}+x-6$$