(2x^2-8x+16)+(x+4) eching

$$( 2 x ^ { 2 } - 8 x + 16 ) + ( x + 4 )$$

Baholash

$$2x^{2}-7x+20$$

Yechim qadamlari

-7x ni olish uchun -8x va x ni birlashtirish.

$$2x^{2}-7x+16+4$$

20 olish uchun 16 va 4'ni qo'shing.

$$2x^{2}-7x+20$$

x ga nisbatan hosilani topish

$$4x-7$$

Yig'indi uchun derivativ qoidasidan foydalanish qadamlari

-7x ni olish uchun -8x va x ni birlashtirish.

$$\frac{\mathrm{d}}{\mathrm{d}x}(2x^{2}-7x+16+4)$$

20 olish uchun 16 va 4'ni qo'shing.

$$\frac{\mathrm{d}}{\mathrm{d}x}(2x^{2}-7x+20)$$

Polinomialning hosilasi bu uning shartlari hosilasining yig‘indisiga teng. Konstant shartning hosilasi 0. ax^{n} ning hosilasi nax^{n-1}.

$$2\times 2x^{2-1}-7x^{1-1}$$

2 ni 2 marotabaga ko'paytirish.

$$4x^{2-1}-7x^{1-1}$$

2 dan 1 ni ayirish.

$$4x^{1}-7x^{1-1}$$

1 dan 1 ni ayirish.

$$4x^{1}-7x^{0}$$

Har qanday t sharti uchun t^{1}=t.

$$4x-7x^{0}$$

Har qanday t sharti uchun (0 bundan mustasno) t^{0}=1.

$$4x-7$$