(2x+i)(4+3i)=(5+yi) eching

$$( 2 x + i ) ( 4 + 3 i ) = ( 5 + y i )$$

x uchun yechish

$$x=\left(\frac{3}{50}+\frac{2}{25}i\right)y+\left(\frac{2}{5}-\frac{4}{5}i\right)$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

2x+i ga 4+3i ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$\left(8+6i\right)x+\left(-3+4i\right)=5+yi$$

Ikkala tarafdan -3+4i ni ayirish.

$$\left(8+6i\right)x=5+yi-\left(-3+4i\right)$$

3-4i hosil qilish uchun -1 va -3+4i ni ko'paytirish.

$$\left(8+6i\right)x=5+yi+\left(3-4i\right)$$

5+\left(3-4i\right) ichida qo‘shishlarni bajaring.

$$\left(8+6i\right)x=yi+8-4i$$

Tenglama standart shaklda.

$$\left(8+6i\right)x=iy+\left(8-4i\right)$$

Ikki tarafini 8+6i ga bo‘ling.

$$\frac{\left(8+6i\right)x}{8+6i}=\frac{iy+\left(8-4i\right)}{8+6i}$$

8+6i ga bo'lish 8+6i ga ko'paytirishni bekor qiladi.

$$x=\frac{iy+\left(8-4i\right)}{8+6i}$$

iy+\left(8-4i\right) ni 8+6i ga bo'lish.

$$x=\left(\frac{3}{50}+\frac{2}{25}i\right)y+\left(\frac{2}{5}-\frac{4}{5}i\right)$$

y uchun yechish

$$y=\left(6-8i\right)x+\left(4+8i\right)$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

2x+i ga 4+3i ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$\left(8+6i\right)x+\left(-3+4i\right)=5+yi$$

Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.

$$5+yi=\left(8+6i\right)x+\left(-3+4i\right)$$

Ikkala tarafdan 5 ni ayirish.

$$yi=\left(8+6i\right)x+\left(-3+4i\right)-5$$

-3+4i-5 ichida qo‘shishlarni bajaring.

$$yi=\left(8+6i\right)x-8+4i$$

Tenglama standart shaklda.

$$iy=\left(8+6i\right)x+\left(-8+4i\right)$$

Ikki tarafini i ga bo‘ling.

$$\frac{iy}{i}=\frac{\left(8+6i\right)x+\left(-8+4i\right)}{i}$$

i ga bo'lish i ga ko'paytirishni bekor qiladi.

$$y=\frac{\left(8+6i\right)x+\left(-8+4i\right)}{i}$$

\left(8+6i\right)x+\left(-8+4i\right) ni i ga bo'lish.

$$y=\left(6-8i\right)x+\left(4+8i\right)$$