(2x+5)(x-1)-(x-1)(x+5)=0 eching

$$( 2 x + 5 ) ( x - 1 ) - ( x - 1 ) ( x + 5 ) = 0$$

x uchun yechish

$$x=0$$

$$x=1$$

Faktorlash qadamlari

2x+5 ga x-1 ni ko‘paytirish orqali distributiv xususiyatdan foydalaning va ifoda sifatida birlashtiring.

$$2x^{2}+3x-5-\left(x-1\right)\left(x+5\right)=0$$

x-1 ga x+5 ni ko‘paytirish orqali distributiv xususiyatdan foydalaning va ifoda sifatida birlashtiring.

$$2x^{2}+3x-5-\left(x^{2}+4x-5\right)=0$$

x^{2}+4x-5 teskarisini topish uchun har birining teskarisini toping.

$$2x^{2}+3x-5-x^{2}-4x+5=0$$

x^{2} ni olish uchun 2x^{2} va -x^{2} ni birlashtirish.

$$x^{2}+3x-5-4x+5=0$$

-x ni olish uchun 3x va -4x ni birlashtirish.

$$x^{2}-x-5+5=0$$

0 olish uchun -5 va 5'ni qo'shing.

$$x^{2}-x=0$$

x omili.

$$x\left(x-1\right)=0$$

Tenglamani yechish uchun x=0 va x-1=0 ni yeching.

$$x=0 x=1$$

Kvadrat tenglamalaridan foydalanish qoidalari

2x+5 ga x-1 ni ko‘paytirish orqali distributiv xususiyatdan foydalaning va ifoda sifatida birlashtiring.

$$2x^{2}+3x-5-\left(x-1\right)\left(x+5\right)=0$$

x-1 ga x+5 ni ko‘paytirish orqali distributiv xususiyatdan foydalaning va ifoda sifatida birlashtiring.

$$2x^{2}+3x-5-\left(x^{2}+4x-5\right)=0$$

x^{2}+4x-5 teskarisini topish uchun har birining teskarisini toping.

$$2x^{2}+3x-5-x^{2}-4x+5=0$$

x^{2} ni olish uchun 2x^{2} va -x^{2} ni birlashtirish.

$$x^{2}+3x-5-4x+5=0$$

-x ni olish uchun 3x va -4x ni birlashtirish.

$$x^{2}-x-5+5=0$$

0 olish uchun -5 va 5'ni qo'shing.

$$x^{2}-x=0$$

Ushbu tenglama standart shaklidadir: ax^{2}+bx+c=0. Kvadrat tenglama formulasida, \frac{-b±\sqrt{b^{2}-4ac}}{2a} 1 ni a, -1 ni b va 0 ni c bilan almashtiring.

$$x=\frac{-\left(-1\right)±\sqrt{1}}{2}$$

1 ning kvadrat ildizini chiqarish.

$$x=\frac{-\left(-1\right)±1}{2}$$

-1 ning teskarisi 1 ga teng.

$$x=\frac{1±1}{2}$$

x=\frac{1±1}{2} tenglamasini yeching, bunda ± musbat. 1 ni 1 ga qo'shish.

$$x=\frac{2}{2}$$

2 ni 2 ga bo'lish.

$$x=1$$

x=\frac{1±1}{2} tenglamasini yeching, bunda ± manfiy. 1 dan 1 ni ayirish.

$$x=\frac{0}{2}$$

0 ni 2 ga bo'lish.

$$x=0$$

Tenglama yechildi.

$$x=1 x=0$$

Kvadratni yakunlash bo'yicha qadamlar

2x+5 ga x-1 ni ko‘paytirish orqali distributiv xususiyatdan foydalaning va ifoda sifatida birlashtiring.

$$2x^{2}+3x-5-\left(x-1\right)\left(x+5\right)=0$$

x-1 ga x+5 ni ko‘paytirish orqali distributiv xususiyatdan foydalaning va ifoda sifatida birlashtiring.

$$2x^{2}+3x-5-\left(x^{2}+4x-5\right)=0$$

x^{2}+4x-5 teskarisini topish uchun har birining teskarisini toping.

$$2x^{2}+3x-5-x^{2}-4x+5=0$$

x^{2} ni olish uchun 2x^{2} va -x^{2} ni birlashtirish.

$$x^{2}+3x-5-4x+5=0$$

-x ni olish uchun 3x va -4x ni birlashtirish.

$$x^{2}-x-5+5=0$$

0 olish uchun -5 va 5'ni qo'shing.

$$x^{2}-x=0$$

-1 ni bo‘lish, x shartining koeffitsienti, 2 ga -\frac{1}{2} olish uchun. Keyin, -\frac{1}{2} ning kvadratini tenglamaning ikkala tarafiga qo‘shing. Ushbu qadam tenglamaning chap qismini mukammal kvadrat sifatida hosil qiladi.

$$x^{2}-x+\left(-\frac{1}{2}\right)^{2}=\left(-\frac{1}{2}\right)^{2}$$

Kasrning ham suratini, ham maxrajini kvadratga ko'paytirib -\frac{1}{2} kvadratini chiqarish.

$$x^{2}-x+\frac{1}{4}=\frac{1}{4}$$

x^{2}-x+\frac{1}{4} omili. Odatda, x^{2}+bx+c mukammal kvadrat bo'lsa, u doimo \left(x+\frac{b}{2}\right)^{2} omil sifatida bo'lishi mumkin.

$$\left(x-\frac{1}{2}\right)^{2}=\frac{1}{4}$$

Tenglamaning ikkala tarafining kvadrat ildizini chiqarish.

$$\sqrt{\left(x-\frac{1}{2}\right)^{2}}=\sqrt{\frac{1}{4}}$$

Qisqartirish.

$$x-\frac{1}{2}=\frac{1}{2} x-\frac{1}{2}=-\frac{1}{2}$$

\frac{1}{2} ni tenglamaning ikkala tarafiga qo'shish.

$$x=1 x=0$$