(2x+3)(6x+2)-6x(2x+13)+8(7x+2) eching

$$( 2 x + 3 ) ( 6 x + 2 ) - 6 x ( 2 x + 13 ) + 8 ( 7 x + 2 )$$

Baholash

$$22$$

Yechim qadamlari

2x+3 ifodaning har bir elementini 6x+2 ifodaning har bir elementiga ko‘paytirish orqali taqsimot qonuni xususiyatlarini qo‘llash mumkin.

$$12x^{2}+4x+18x+6-6x\left(2x+13\right)+8\left(7x+2\right)$$

22x ni olish uchun 4x va 18x ni birlashtirish.

$$12x^{2}+22x+6-6x\left(2x+13\right)+8\left(7x+2\right)$$

8 ga 7x+2 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$12x^{2}+22x+6-6x\left(2x+13\right)+56x+16$$

-6x ga 2x+13 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$12x^{2}+22x+6-12x^{2}-78x+56x+16$$

0 ni olish uchun 12x^{2} va -12x^{2} ni birlashtirish.

$$22x+6-78x+56x+16$$

-56x ni olish uchun 22x va -78x ni birlashtirish.

$$-56x+6+56x+16$$

0 ni olish uchun -56x va 56x ni birlashtirish.

$$6+16$$

22 olish uchun 6 va 16'ni qo'shing.

$$22$$

Omil

$$2\times 11$$

Yechim qadamlari

2 omili.

$$2\left(\left(2x+3\right)\left(3x+1\right)-3x\left(2x+13\right)+4\left(7x+2\right)\right)$$

Qisqartirish.

$$22$$