(2a-3a)^2-[(1/2x+1/2x)^2]^3-4 eching

$$( 2 a - 3 a ) ^ { 2 } - [ ( \frac { 1 } { 2 } x + \frac { 1 } { 2 } x ) ^ { 2 } ] ^ { 3 } - 4$$

Baholash

$$-x^{6}+a^{2}-4$$

Yechim qadamlari

Daraja ko‘rsatkichini boshqa ko‘rsatkichga oshirish uchun, darajalarini ko‘paytiring. 2 va 3 ni ko‘paytirib, 6 ni oling.

$$\left(2a-3a\right)^{2}-\left(\frac{1}{2}x+\frac{1}{2}x\right)^{6}-4$$

-a ni olish uchun 2a va -3a ni birlashtirish.

$$\left(-a\right)^{2}-\left(\frac{1}{2}x+\frac{1}{2}x\right)^{6}-4$$

\left(-a\right)^{2} ni kengaytirish.

$$\left(-1\right)^{2}a^{2}-\left(\frac{1}{2}x+\frac{1}{2}x\right)^{6}-4$$

2 daraja ko‘rsatkichini -1 ga hisoblang va 1 ni qiymatni oling.

$$1a^{2}-\left(\frac{1}{2}x+\frac{1}{2}x\right)^{6}-4$$

x ni olish uchun \frac{1}{2}x va \frac{1}{2}x ni birlashtirish.

$$1a^{2}-x^{6}-4$$

Har qanday t sharti uchun t\times 1=t va 1t=t.

$$a^{2}-x^{6}-4$$

Kengaytirish

$$-x^{6}+a^{2}-4$$

Yechim qadamlari

Daraja ko‘rsatkichini boshqa ko‘rsatkichga oshirish uchun, darajalarini ko‘paytiring. 2 va 3 ni ko‘paytirib, 6 ni oling.

$$\left(2a-3a\right)^{2}-\left(\frac{1}{2}x+\frac{1}{2}x\right)^{6}-4$$

-a ni olish uchun 2a va -3a ni birlashtirish.

$$\left(-a\right)^{2}-\left(\frac{1}{2}x+\frac{1}{2}x\right)^{6}-4$$

\left(-a\right)^{2} ni kengaytirish.

$$\left(-1\right)^{2}a^{2}-\left(\frac{1}{2}x+\frac{1}{2}x\right)^{6}-4$$

2 daraja ko‘rsatkichini -1 ga hisoblang va 1 ni qiymatni oling.

$$1a^{2}-\left(\frac{1}{2}x+\frac{1}{2}x\right)^{6}-4$$

x ni olish uchun \frac{1}{2}x va \frac{1}{2}x ni birlashtirish.

$$1a^{2}-x^{6}-4$$

Har qanday t sharti uchun t\times 1=t va 1t=t.

$$a^{2}-x^{6}-4$$