(2a+3)(2a-1)-(2a+1)^2 eching

$$( 2 a + 3 ) ( 2 a - 1 ) - ( 2 a + 1 ) ^ { 2 }$$

Baholash

$$-4$$

Yechim qadamlari

2a+3 ga 2a-1 ni ko‘paytirish orqali distributiv xususiyatdan foydalaning va ifoda sifatida birlashtiring.

$$4a^{2}+4a-3-\left(2a+1\right)^{2}$$

\left(p+q\right)^{2}=p^{2}+2pq+q^{2} binom teoremasini \left(2a+1\right)^{2} kengaytirilishi uchun ishlating.

$$4a^{2}+4a-3-\left(4a^{2}+4a+1\right)$$

4a^{2}+4a+1 teskarisini topish uchun har birining teskarisini toping.

$$4a^{2}+4a-3-4a^{2}-4a-1$$

0 ni olish uchun 4a^{2} va -4a^{2} ni birlashtirish.

$$4a-3-4a-1$$

0 ni olish uchun 4a va -4a ni birlashtirish.

$$-3-1$$

-4 olish uchun -3 dan 1 ni ayirish.

$$-4$$

Omil

$$-4$$