(2a+1)(2a-1)(9a^2+3)-(-6a^2)^2-(12a^3-8a):(4a) eching

$$( 2 a + 1 ) ( 2 a - 1 ) ( 9 a ^ { 2 } + 3 ) - ( - 6 a ^ { 2 } ) ^ { 2 } - ( 12 a ^ { 3 } - 8 a ) : ( 4 a )$$

Baholash

$$-1$$

Qisqa yechim qadamlari

\left(-6a^{2}\right)^{2} ni kengaytirish.

$$\left(2a+1\right)\left(2a-1\right)\left(9a^{2}+3\right)-\left(-6\right)^{2}\left(a^{2}\right)^{2}-\frac{12a^{3}-8a}{4a}$$

Daraja ko‘rsatkichini boshqa ko‘rsatkichga oshirish uchun, darajalarini ko‘paytiring. 2 va 2 ni ko‘paytirib, 4 ni oling.

$$\left(2a+1\right)\left(2a-1\right)\left(9a^{2}+3\right)-\left(-6\right)^{2}a^{4}-\frac{12a^{3}-8a}{4a}$$

2 daraja ko‘rsatkichini -6 ga hisoblang va 36 ni qiymatni oling.

$$\left(2a+1\right)\left(2a-1\right)\left(9a^{2}+3\right)-36a^{4}-\frac{12a^{3}-8a}{4a}$$

\frac{12a^{3}-8a}{4a} ichida hali faktorlanmagan ifodalarni faktorlang.

$$\left(2a+1\right)\left(2a-1\right)\left(9a^{2}+3\right)-36a^{4}-\frac{4a\left(3a^{2}-2\right)}{4a}$$

Surat va maxrajdagi ikkala 4a ni qisqartiring.

$$\left(2a+1\right)\left(2a-1\right)\left(9a^{2}+3\right)-36a^{4}-\left(3a^{2}-2\right)$$

3a^{2}-2 teskarisini topish uchun har birining teskarisini toping.

$$\left(2a+1\right)\left(2a-1\right)\left(9a^{2}+3\right)-36a^{4}-3a^{2}+2$$

2a+1 ga 2a-1 ni ko‘paytirish orqali distributiv xususiyatdan foydalaning va ifoda sifatida birlashtiring.

$$\left(4a^{2}-1\right)\left(9a^{2}+3\right)-36a^{4}-3a^{2}+2$$

4a^{2}-1 ga 9a^{2}+3 ni ko‘paytirish orqali distributiv xususiyatdan foydalaning va ifoda sifatida birlashtiring.

$$36a^{4}+3a^{2}-3-36a^{4}-3a^{2}+2$$

0 ni olish uchun 36a^{4} va -36a^{4} ni birlashtirish.

$$3a^{2}-3-3a^{2}+2$$

0 ni olish uchun 3a^{2} va -3a^{2} ni birlashtirish.

$$-3+2$$

-1 olish uchun -3 va 2'ni qo'shing.

$$-1$$

Omil

$$-1$$