(2sqrt{7}-3sqrt{2})(2sqrt{7}+3sqrt{2})= eching

$$( 2 \sqrt { 7 } - 3 \sqrt { 2 } ) ( 2 \sqrt { 7 } + 3 \sqrt { 2 } ) =$$

Baholash

$$10$$

Yechim qadamlari

Ko‘paytirish qoida yordamida turli kvadratlarga aylantirilishi mumkin: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.

$$\left(2\sqrt{7}\right)^{2}-\left(3\sqrt{2}\right)^{2}$$

\left(2\sqrt{7}\right)^{2} ni kengaytirish.

$$2^{2}\left(\sqrt{7}\right)^{2}-\left(3\sqrt{2}\right)^{2}$$

2 daraja ko‘rsatkichini 2 ga hisoblang va 4 ni qiymatni oling.

$$4\left(\sqrt{7}\right)^{2}-\left(3\sqrt{2}\right)^{2}$$

\sqrt{7} kvadrati – 7.

$$4\times 7-\left(3\sqrt{2}\right)^{2}$$

28 hosil qilish uchun 4 va 7 ni ko'paytirish.

$$28-\left(3\sqrt{2}\right)^{2}$$

\left(3\sqrt{2}\right)^{2} ni kengaytirish.

$$28-3^{2}\left(\sqrt{2}\right)^{2}$$

2 daraja ko‘rsatkichini 3 ga hisoblang va 9 ni qiymatni oling.

$$28-9\left(\sqrt{2}\right)^{2}$$

\sqrt{2} kvadrati – 2.

$$28-9\times 2$$

18 hosil qilish uchun 9 va 2 ni ko'paytirish.

$$28-18$$

10 olish uchun 28 dan 18 ni ayirish.

$$10$$

Omil

$$2\times 5$$