(2^5+sqrt{36})*sqrt{2^2+72:6}= eching

$$( 2 ^ { 5 } + \sqrt { 36 } ) \cdot \sqrt { 2 ^ { 2 } + 72 : 6 } =$$

Baholash

$$152$$

Yechim qadamlari

5 daraja ko‘rsatkichini 2 ga hisoblang va 32 ni qiymatni oling.

$$\left(32+\sqrt{36}\right)\sqrt{2^{2}+\frac{72}{6}}$$

36 ning kvadrat ildizini hisoblab, 6 natijaga ega bo‘ling.

$$\left(32+6\right)\sqrt{2^{2}+\frac{72}{6}}$$

38 olish uchun 32 va 6'ni qo'shing.

$$38\sqrt{2^{2}+\frac{72}{6}}$$

2 daraja ko‘rsatkichini 2 ga hisoblang va 4 ni qiymatni oling.

$$38\sqrt{4+\frac{72}{6}}$$

12 ni olish uchun 72 ni 6 ga bo‘ling.

$$38\sqrt{4+12}$$

16 olish uchun 4 va 12'ni qo'shing.

$$38\sqrt{16}$$

16 ning kvadrat ildizini hisoblab, 4 natijaga ega bo‘ling.

$$38\times 4$$

152 hosil qilish uchun 38 va 4 ni ko'paytirish.

$$152$$

Omil

$$2^{3}\times 19$$