(14*10^0)(2*10^-3) eching

$$( 14 \times 10 ^ { 0 } ) ( 2 \times 10 ^ { - 3 } )$$

Baholash

$$\frac{7}{250}=0,028$$

Yechim qadamlari

Ayni asosning daraja ko‘rsatkichlarini ko‘paytirish uchun ularning darajalarini qo‘shing. 0 va -3 ni qo‘shib, -3 ni oling.

$$14\times 10^{-3}\times 2$$

-3 daraja ko‘rsatkichini 10 ga hisoblang va \frac{1}{1000} ni qiymatni oling.

$$14\times \frac{1}{1000}\times 2$$

\frac{7}{500} hosil qilish uchun 14 va \frac{1}{1000} ni ko'paytirish.

$$\frac{7}{500}\times 2$$

\frac{7}{250} hosil qilish uchun \frac{7}{500} va 2 ni ko'paytirish.

$$\frac{7}{250}$$

Omil

$$\frac{7}{2 \cdot 5 ^ {3}} = 0,028$$