(10*x+y)=5x(x+y) eching

$$( 10 * x + y ) = 5 x ( x + y )$$

y uchun yechish

$$y=-\frac{5x\left(2-x\right)}{1-5x}$$

$$x\neq \frac{1}{5}$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

5x ga x+y ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$10x+y=5x^{2}+5xy$$

Ikkala tarafdan 5xy ni ayirish.

$$10x+y-5xy=5x^{2}$$

Ikkala tarafdan 10x ni ayirish.

$$y-5xy=5x^{2}-10x$$

y'ga ega bo'lgan barcha shartlarni birlashtirish.

$$\left(1-5x\right)y=5x^{2}-10x$$

Ikki tarafini 1-5x ga bo‘ling.

$$\frac{\left(1-5x\right)y}{1-5x}=\frac{5x\left(x-2\right)}{1-5x}$$

1-5x ga bo'lish 1-5x ga ko'paytirishni bekor qiladi.

$$y=\frac{5x\left(x-2\right)}{1-5x}$$

x uchun yechish

$$x=-\frac{\sqrt{25y^{2}-80y+100}}{10}-\frac{y}{2}+1$$

$$x=\frac{\sqrt{25y^{2}-80y+100}}{10}-\frac{y}{2}+1$$