(1-k)x^2+x+(1-k)=0t eching

$$( 1 - k ) x ^ { 2 } + x + ( 1 - k ) = 0 t$$

k uchun yechish

$$k=\frac{x^{2}+x+1}{x^{2}+1}$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

1-k ga x^{2} ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$x^{2}-kx^{2}+x+1-k=0t$$

Har qanday sonni nolga ko‘paytirsangiz, nol chiqadi.

$$x^{2}-kx^{2}+x+1-k=0$$

Ikkala tarafdan x^{2} ni ayirish. Har qanday sonni noldan ayirsangiz, o‘zining manfiyi chiqadi.

$$-kx^{2}+x+1-k=-x^{2}$$

Ikkala tarafdan x ni ayirish.

$$-kx^{2}+1-k=-x^{2}-x$$

Ikkala tarafdan 1 ni ayirish.

$$-kx^{2}-k=-x^{2}-x-1$$

k'ga ega bo'lgan barcha shartlarni birlashtirish.

$$\left(-x^{2}-1\right)k=-x^{2}-x-1$$

Ikki tarafini -x^{2}-1 ga bo‘ling.

$$\frac{\left(-x^{2}-1\right)k}{-x^{2}-1}=\frac{-x^{2}-x-1}{-x^{2}-1}$$

-x^{2}-1 ga bo'lish -x^{2}-1 ga ko'paytirishni bekor qiladi.

$$k=\frac{-x^{2}-x-1}{-x^{2}-1}$$

-x^{2}-x-1 ni -x^{2}-1 ga bo'lish.

$$k=\frac{x^{2}+x+1}{x^{2}+1}$$

t uchun yechish

$$t\in \mathrm{R}$$

$$k=\frac{x^{2}+x+1}{x^{2}+1}$$