(1-2y)^2=(2y-1)(2y+7) eching

$$( 1 - 2 y ) ^ { 2 } = ( 2 y - 1 ) ( 2 y + 7 )$$

y uchun yechish

$$y=\frac{1}{2}=0,5$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

\left(a-b\right)^{2}=a^{2}-2ab+b^{2} binom teoremasini \left(1-2y\right)^{2} kengaytirilishi uchun ishlating.

$$1-4y+4y^{2}=\left(2y-1\right)\left(2y+7\right)$$

2y-1 ga 2y+7 ni ko‘paytirish orqali distributiv xususiyatdan foydalaning va ifoda sifatida birlashtiring.

$$1-4y+4y^{2}=4y^{2}+12y-7$$

Ikkala tarafdan 4y^{2} ni ayirish.

$$1-4y+4y^{2}-4y^{2}=12y-7$$

0 ni olish uchun 4y^{2} va -4y^{2} ni birlashtirish.

$$1-4y=12y-7$$

Ikkala tarafdan 12y ni ayirish.

$$1-4y-12y=-7$$

-16y ni olish uchun -4y va -12y ni birlashtirish.

$$1-16y=-7$$

Ikkala tarafdan 1 ni ayirish.

$$-16y=-7-1$$

-8 olish uchun -7 dan 1 ni ayirish.

$$-16y=-8$$

Ikki tarafini -16 ga bo‘ling.

$$y=\frac{-8}{-16}$$

\frac{-8}{-16} ulushini -8 ni chiqarib, bekor qilish hisobiga eng past shartlarga kamaytiring.

$$y=\frac{1}{2}$$