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x uchun yechish
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1,02^{x}=2
Tenglamani yechish uchun eksponent va logaritmlarning qoidalaridan foydalanish.
\log(1,02^{x})=\log(2)
Tenglamaning ikkala tarafiga tegishli logaritmni chiqarish.
x\log(1,02)=\log(2)
Darajaga ko'tarigan logaritm raqami raqam logaritmining darajasidir.
x=\frac{\log(2)}{\log(1,02)}
Ikki tarafini \log(1,02) ga bo‘ling.
x=\log_{1,02}\left(2\right)
Asosiy tenglamani almashtirish orqali \frac{\log(a)}{\log(b)}=\log_{b}\left(a\right).