(-x+3)^2-2(2x-1)^2 eching

$$( - x + 3 ) ^ { 2 } - 2 ( 2 x - 1 ) ^ { 2 }$$

Baholash

$$7+2x-7x^{2}$$

Yechim qadamlari

\left(a+b\right)^{2}=a^{2}+2ab+b^{2} binom teoremasini \left(-x+3\right)^{2} kengaytirilishi uchun ishlating.

$$\left(-x\right)^{2}+6\left(-x\right)+9-2\left(2x-1\right)^{2}$$

2 daraja ko‘rsatkichini -x ga hisoblang va x^{2} ni qiymatni oling.

$$x^{2}+6\left(-x\right)+9-2\left(2x-1\right)^{2}$$

\left(a-b\right)^{2}=a^{2}-2ab+b^{2} binom teoremasini \left(2x-1\right)^{2} kengaytirilishi uchun ishlating.

$$x^{2}+6\left(-x\right)+9-2\left(4x^{2}-4x+1\right)$$

-2 ga 4x^{2}-4x+1 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$x^{2}+6\left(-x\right)+9-8x^{2}+8x-2$$

-7x^{2} ni olish uchun x^{2} va -8x^{2} ni birlashtirish.

$$-7x^{2}+6\left(-x\right)+9+8x-2$$

7 olish uchun 9 dan 2 ni ayirish.

$$-7x^{2}+6\left(-x\right)+7+8x$$

-6 hosil qilish uchun 6 va -1 ni ko'paytirish.

$$-7x^{2}-6x+7+8x$$

2x ni olish uchun -6x va 8x ni birlashtirish.

$$-7x^{2}+2x+7$$

Kengaytirish

$$7+2x-7x^{2}$$

Yechim qadamlari

\left(a+b\right)^{2}=a^{2}+2ab+b^{2} binom teoremasini \left(-x+3\right)^{2} kengaytirilishi uchun ishlating.

$$\left(-x\right)^{2}+6\left(-x\right)+9-2\left(2x-1\right)^{2}$$

2 daraja ko‘rsatkichini -x ga hisoblang va x^{2} ni qiymatni oling.

$$x^{2}+6\left(-x\right)+9-2\left(2x-1\right)^{2}$$

\left(a-b\right)^{2}=a^{2}-2ab+b^{2} binom teoremasini \left(2x-1\right)^{2} kengaytirilishi uchun ishlating.

$$x^{2}+6\left(-x\right)+9-2\left(4x^{2}-4x+1\right)$$

-2 ga 4x^{2}-4x+1 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$x^{2}+6\left(-x\right)+9-8x^{2}+8x-2$$

-7x^{2} ni olish uchun x^{2} va -8x^{2} ni birlashtirish.

$$-7x^{2}+6\left(-x\right)+9+8x-2$$

7 olish uchun 9 dan 2 ni ayirish.

$$-7x^{2}+6\left(-x\right)+7+8x$$

-6 hosil qilish uchun 6 va -1 ni ko'paytirish.

$$-7x^{2}-6x+7+8x$$

2x ni olish uchun -6x va 8x ni birlashtirish.

$$-7x^{2}+2x+7$$