(-5+3)(P+1)=(-p+3)(5-1) eching

$$( - 5 + 3 ) ( P + 1 ) = ( - p + 3 ) ( 5 - 1 )$$

P uchun yechish

$$P=2p-7$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

-2 olish uchun -5 va 3'ni qo'shing.

$$-2\left(P+1\right)=\left(-p+3\right)\left(5-1\right)$$

-2 ga P+1 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$-2P-2=\left(-p+3\right)\left(5-1\right)$$

4 olish uchun 5 dan 1 ni ayirish.

$$-2P-2=\left(-p+3\right)\times 4$$

-p+3 ga 4 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$-2P-2=4\left(-p\right)+12$$

2 ni ikki tarafga qo’shing.

$$-2P=4\left(-p\right)+12+2$$

14 olish uchun 12 va 2'ni qo'shing.

$$-2P=4\left(-p\right)+14$$

-4 hosil qilish uchun 4 va -1 ni ko'paytirish.

$$-2P=-4p+14$$

Tenglama standart shaklda.

$$-2P=14-4p$$

Ikki tarafini -2 ga bo‘ling.

$$\frac{-2P}{-2}=\frac{14-4p}{-2}$$

-2 ga bo'lish -2 ga ko'paytirishni bekor qiladi.

$$P=\frac{14-4p}{-2}$$

-4p+14 ni -2 ga bo'lish.

$$P=2p-7$$

p uchun yechish

$$p=\frac{P+7}{2}$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

-2 olish uchun -5 va 3'ni qo'shing.

$$-2\left(P+1\right)=\left(-p+3\right)\left(5-1\right)$$

-2 ga P+1 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$-2P-2=\left(-p+3\right)\left(5-1\right)$$

4 olish uchun 5 dan 1 ni ayirish.

$$-2P-2=\left(-p+3\right)\times 4$$

-p+3 ga 4 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$-2P-2=4\left(-p\right)+12$$

Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.

$$4\left(-p\right)+12=-2P-2$$

Ikkala tarafdan 12 ni ayirish.

$$4\left(-p\right)=-2P-2-12$$

-14 olish uchun -2 dan 12 ni ayirish.

$$4\left(-p\right)=-2P-14$$

-4 hosil qilish uchun 4 va -1 ni ko'paytirish.

$$-4p=-2P-14$$

Ikki tarafini -4 ga bo‘ling.

$$\frac{-4p}{-4}=\frac{-2P-14}{-4}$$

-4 ga bo'lish -4 ga ko'paytirishni bekor qiladi.

$$p=\frac{-2P-14}{-4}$$

-2P-14 ni -4 ga bo'lish.

$$p=\frac{P+7}{2}$$