((0*x)+(1*5)+(2*6)+(3*3)+(4*2))div(x+5+6+3+2)=2 eching

$$( ( 0 \times x ) + ( 1 \times 5 ) + ( 2 \times 6 ) + ( 3 \times 3 ) + ( 4 \times 2 ) ) \div ( x + 5 + 6 + 3 + 2 ) = 2$$

x uchun yechish

$$x=1$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

x qiymati -16 teng bo‘lmaydi, chunki nolga bo‘lish mumkin emas. Tenglamaning ikkala tarafini x+16 ga ko'paytirish.

$$0x+1\times 5+2\times 6+3\times 3+4\times 2=2\left(x+16\right)$$

Ko‘paytirishlarni bajaring.

$$0x+5+12+9+8=2\left(x+16\right)$$

Har qanday sonni nolga ko‘paytirsangiz, nol chiqadi.

$$0+5+12+9+8=2\left(x+16\right)$$

5 olish uchun 0 va 5'ni qo'shing.

$$5+12+9+8=2\left(x+16\right)$$

17 olish uchun 5 va 12'ni qo'shing.

$$17+9+8=2\left(x+16\right)$$

26 olish uchun 17 va 9'ni qo'shing.

$$26+8=2\left(x+16\right)$$

34 olish uchun 26 va 8'ni qo'shing.

$$34=2\left(x+16\right)$$

2 ga x+16 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$34=2x+32$$

Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.

$$2x+32=34$$

Ikkala tarafdan 32 ni ayirish.

$$2x=34-32$$

2 olish uchun 34 dan 32 ni ayirish.

$$2x=2$$

Ikki tarafini 2 ga bo‘ling.

$$x=\frac{2}{2}$$

1 ni olish uchun 2 ni 2 ga bo‘ling.

$$x=1$$