(sqrt{x}-sqrt{2})(sqrt{x}+sqrt{2}) eching

$$( \sqrt { x } - \sqrt { 2 } ) ( \sqrt { x } + \sqrt { 2 } )$$

Baholash

$$x-2$$

Yechim qadamlari

Ko‘paytirish qoida yordamida turli kvadratlarga aylantirilishi mumkin: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.

$$\left(\sqrt{x}\right)^{2}-\left(\sqrt{2}\right)^{2}$$

2 daraja ko‘rsatkichini \sqrt{x} ga hisoblang va x ni qiymatni oling.

$$x-\left(\sqrt{2}\right)^{2}$$

\sqrt{2} kvadrati – 2.

$$x-2$$

x ga nisbatan hosilani topish

$$1$$

Yig'indi uchun derivativ qoidasidan foydalanish qadamlari

Hisoblang: \left(\sqrt{x}-\sqrt{2}\right)\left(\sqrt{x}+\sqrt{2}\right). Ko‘paytirish qoida yordamida turli kvadratlarga aylantirilishi mumkin: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.

$$\frac{\mathrm{d}}{\mathrm{d}x}(\left(\sqrt{x}\right)^{2}-\left(\sqrt{2}\right)^{2})$$

2 daraja ko‘rsatkichini \sqrt{x} ga hisoblang va x ni qiymatni oling.

$$\frac{\mathrm{d}}{\mathrm{d}x}(x-\left(\sqrt{2}\right)^{2})$$

\sqrt{2} kvadrati – 2.

$$\frac{\mathrm{d}}{\mathrm{d}x}(x-2)$$

Polinomialning hosilasi bu uning shartlari hosilasining yig‘indisiga teng. Konstant shartning hosilasi 0. ax^{n} ning hosilasi nax^{n-1}.

$$x^{1-1}$$

1 dan 1 ni ayirish.

$$x^{0}$$

Har qanday t sharti uchun (0 bundan mustasno) t^{0}=1.

$$1$$