(sqrt{99}-sqrt{11})^2 eching

$$( \sqrt { 99 } - \sqrt { 11 } ) ^ { 2 }$$

Baholash

$$44$$

Yechim qadamlari

Faktor: 99=3^{2}\times 11. \sqrt{3^{2}\times 11} koʻpaytmasining kvadrat ildizini \sqrt{3^{2}}\sqrt{11} kvadrat ildizlarining koʻpaytmasi sifatida qayta yozing. 3^{2} ning kvadrat ildizini chiqarish.

$$\left(3\sqrt{11}-\sqrt{11}\right)^{2}$$

2\sqrt{11} ni olish uchun 3\sqrt{11} va -\sqrt{11} ni birlashtirish.

$$\left(2\sqrt{11}\right)^{2}$$

\left(2\sqrt{11}\right)^{2} ni kengaytirish.

$$2^{2}\left(\sqrt{11}\right)^{2}$$

2 daraja ko‘rsatkichini 2 ga hisoblang va 4 ni qiymatni oling.

$$4\left(\sqrt{11}\right)^{2}$$

\sqrt{11} kvadrati – 11.

$$4\times 11$$

44 hosil qilish uchun 4 va 11 ni ko'paytirish.

$$44$$

Omil

$$2^{2}\times 11$$