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\left(\sqrt{7}\right)^{2}+2\sqrt{7}+1
\left(a+b\right)^{2}=a^{2}+2ab+b^{2} binom teoremasini \left(\sqrt{7}+1\right)^{2} kengaytirilishi uchun ishlating.
7+2\sqrt{7}+1
\sqrt{7} kvadrati – 7.
8+2\sqrt{7}
8 olish uchun 7 va 1'ni qo'shing.
\left(\sqrt{7}\right)^{2}+2\sqrt{7}+1
\left(a+b\right)^{2}=a^{2}+2ab+b^{2} binom teoremasini \left(\sqrt{7}+1\right)^{2} kengaytirilishi uchun ishlating.
7+2\sqrt{7}+1
\sqrt{7} kvadrati – 7.
8+2\sqrt{7}
8 olish uchun 7 va 1'ni qo'shing.