(left(1+2iright)i^5+{left(1-i/1+iright)}^3) eching

$$( \left( 1+2i \right) { i }^{ 5 } + { \left( \frac{ 1-i }{ 1+i } \right) }^{ 3 } )$$

Baholash

$$-2+2i$$

Yechim qadamlari

5 daraja ko‘rsatkichini i ga hisoblang va i ni qiymatni oling.

$$\left(1+2i\right)i+\left(\frac{1-i}{1+i}\right)^{3}$$

-2+i hosil qilish uchun 1+2i va i ni ko'paytirish.

$$-2+i+\left(\frac{1-i}{1+i}\right)^{3}$$

\frac{1-i}{1+i}ning surat va maxrajini murakkab tutash maxraj 1-i bilan ko‘paytiring.

$$-2+i+\left(\frac{\left(1-i\right)\left(1-i\right)}{\left(1+i\right)\left(1-i\right)}\right)^{3}$$

\frac{\left(1-i\right)\left(1-i\right)}{\left(1+i\right)\left(1-i\right)} ichidagi ko‘paytirishlarni bajaring.

$$-2+i+\left(\frac{-2i}{2}\right)^{3}$$

-i ni olish uchun -2i ni 2 ga bo‘ling.

$$-2+i+\left(-i\right)^{3}$$

3 daraja ko‘rsatkichini -i ga hisoblang va i ni qiymatni oling.

$$-2+i+i$$

-2+2i olish uchun -2+i va i'ni qo'shing.

$$-2+2i$$

Ashyoviy qism

$$-2$$

Yechim qadamlari

5 daraja ko‘rsatkichini i ga hisoblang va i ni qiymatni oling.

$$Re(\left(1+2i\right)i+\left(\frac{1-i}{1+i}\right)^{3})$$

-2+i hosil qilish uchun 1+2i va i ni ko'paytirish.

$$Re(-2+i+\left(\frac{1-i}{1+i}\right)^{3})$$

\frac{1-i}{1+i}ning surat va maxrajini murakkab tutash maxraj 1-i bilan ko‘paytiring.

$$Re(-2+i+\left(\frac{\left(1-i\right)\left(1-i\right)}{\left(1+i\right)\left(1-i\right)}\right)^{3})$$

\frac{\left(1-i\right)\left(1-i\right)}{\left(1+i\right)\left(1-i\right)} ichidagi ko‘paytirishlarni bajaring.

$$Re(-2+i+\left(\frac{-2i}{2}\right)^{3})$$

-i ni olish uchun -2i ni 2 ga bo‘ling.

$$Re(-2+i+\left(-i\right)^{3})$$

3 daraja ko‘rsatkichini -i ga hisoblang va i ni qiymatni oling.

$$Re(-2+i+i)$$

-2+2i olish uchun -2+i va i'ni qo'shing.

$$Re(-2+2i)$$

-2+2i ning real qismi – -2.

$$-2$$