(9x^3y/y^-3)^1/2 eching

$$( \frac { 9 x ^ { 3 } y } { y ^ { - 3 } } ) ^ { 1 / 2 }$$

Baholash

$$3x^{\frac{3}{2}}y^{2}$$

Yechim qadamlari

Ayni asosning daraja ko'rsatkichi bo'lish uchun maxrajning darajasini surat darajasidan bo'ling.

$$\left(9x^{3}y^{4}\right)^{\frac{1}{2}}$$

\left(9x^{3}y^{4}\right)^{\frac{1}{2}} ni kengaytirish.

$$9^{\frac{1}{2}}\left(x^{3}\right)^{\frac{1}{2}}\left(y^{4}\right)^{\frac{1}{2}}$$

Daraja ko‘rsatkichini boshqa ko‘rsatkichga oshirish uchun, darajalarini ko‘paytiring. 3 va \frac{1}{2} ni ko‘paytirib, \frac{3}{2} ni oling.

$$9^{\frac{1}{2}}x^{\frac{3}{2}}\left(y^{4}\right)^{\frac{1}{2}}$$

Daraja ko‘rsatkichini boshqa ko‘rsatkichga oshirish uchun, darajalarini ko‘paytiring. 4 va \frac{1}{2} ni ko‘paytirib, 2 ni oling.

$$9^{\frac{1}{2}}x^{\frac{3}{2}}y^{2}$$

\frac{1}{2} daraja ko‘rsatkichini 9 ga hisoblang va 3 ni qiymatni oling.

$$3x^{\frac{3}{2}}y^{2}$$

x ga nisbatan hosilani topish

$$\frac{9\sqrt{x}y^{2}}{2}$$