(8/3x^3-5/17x^2+9x-2/34)+(7/6x^3+frac{3}{34}x^2+frac{5}{17}) eching

$$( \frac { 8 } { 3 } x ^ { 3 } - \frac { 5 } { 17 } x ^ { 2 } + 9 x - \frac { 2 } { 34 } ) + ( \frac { 7 } { 6 } x ^ { 3 } + \frac { 3 } { 34 } x ^ { 2 } + \frac { 5 } { 17 } )$$

Baholash

$$\frac{23x^{3}}{6}-\frac{7x^{2}}{34}+9x+\frac{4}{17}$$

Yechim qadamlari

\frac{2}{34} ulushini 2 ni chiqarib, bekor qilish hisobiga eng past shartlarga kamaytiring.

$$\frac{8}{3}x^{3}-\frac{5}{17}x^{2}+9x-\frac{1}{17}+\frac{7}{6}x^{3}+\frac{3}{34}x^{2}+\frac{5}{17}$$

\frac{23}{6}x^{3} ni olish uchun \frac{8}{3}x^{3} va \frac{7}{6}x^{3} ni birlashtirish.

$$\frac{23}{6}x^{3}-\frac{5}{17}x^{2}+9x-\frac{1}{17}+\frac{3}{34}x^{2}+\frac{5}{17}$$

-\frac{7}{34}x^{2} ni olish uchun -\frac{5}{17}x^{2} va \frac{3}{34}x^{2} ni birlashtirish.

$$\frac{23}{6}x^{3}-\frac{7}{34}x^{2}+9x-\frac{1}{17}+\frac{5}{17}$$

\frac{4}{17} olish uchun -\frac{1}{17} va \frac{5}{17}'ni qo'shing.

$$\frac{23}{6}x^{3}-\frac{7}{34}x^{2}+9x+\frac{4}{17}$$

Omil

$$\frac{391x^{3}-21x^{2}+918x+24}{102}$$

Yechim qadamlari

\frac{1}{102} omili. Koʻphadli 391x^{3}-21x^{2}+918x+24 faktorlanmagan, chunki unda ratsional ildizlar topilmadi.

$$\frac{391x^{3}-21x^{2}+918x+24}{102}$$