(1/5(x-10)>1/10-2/15 eching

$$( \frac { 1 } { 5 } ( x - 10 ) > \frac { 1 } { 10 } - \frac { 2 } { 15 }$$

x uchun yechish

$$x>\frac{59}{6}$$

Yechim qadamlari

\frac{1}{5} ga x-10 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$\frac{1}{5}x+\frac{1}{5}\left(-10\right)>\frac{1}{10}-\frac{2}{15}$$

\frac{-10}{5} hosil qilish uchun \frac{1}{5} va -10 ni ko'paytirish.

$$\frac{1}{5}x+\frac{-10}{5}>\frac{1}{10}-\frac{2}{15}$$

-2 ni olish uchun -10 ni 5 ga bo‘ling.

$$\frac{1}{5}x-2>\frac{1}{10}-\frac{2}{15}$$

10 va 15 ning eng kichik umumiy karralisi 30 ga teng. \frac{1}{10} va \frac{2}{15} ni 30 maxraj bilan kasrlarga aylantirib oling.

$$\frac{1}{5}x-2>\frac{3}{30}-\frac{4}{30}$$

\frac{3}{30} va \frac{4}{30} da bir xil maxraji bor, ularning suratini ayirish orqali ayiring.

$$\frac{1}{5}x-2>\frac{3-4}{30}$$

-1 olish uchun 3 dan 4 ni ayirish.

$$\frac{1}{5}x-2>-\frac{1}{30}$$

2 ni ikki tarafga qo’shing.

$$\frac{1}{5}x>-\frac{1}{30}+2$$

2 ni \frac{60}{30} kasrga o‘giring.

$$\frac{1}{5}x>-\frac{1}{30}+\frac{60}{30}$$

-\frac{1}{30} va \frac{60}{30} da bir xil maxraji bor, ularning suratini qo‘shish orqali qo‘shing.

$$\frac{1}{5}x>\frac{-1+60}{30}$$

59 olish uchun -1 va 60'ni qo'shing.

$$\frac{1}{5}x>\frac{59}{30}$$

Ikki tarafini 5 va teskari kasri \frac{1}{5} ga ko‘paytiring. \frac{1}{5} musbat bo‘lgani uchun, tengsizlik yo‘nalishi o‘zgarmaydi.

$$x>\frac{59}{30}\times 5$$

\frac{59}{30}\times 5 ni yagona kasrga aylantiring.

$$x>\frac{59\times 5}{30}$$

295 hosil qilish uchun 59 va 5 ni ko'paytirish.

$$x>\frac{295}{30}$$

\frac{295}{30} ulushini 5 ni chiqarib, bekor qilish hisobiga eng past shartlarga kamaytiring.

$$x>\frac{59}{6}$$