y uchun yechish (complex solution)
y=\frac{2}{x^{3}+1}
x\neq -1\text{ and }x\neq \frac{-\sqrt{3}i+1}{2}\text{ and }x\neq \frac{1+\sqrt{3}i}{2}
y uchun yechish
y=\frac{2}{x^{3}+1}
x\neq -1
x uchun yechish (complex solution)
x=e^{\frac{2\pi i}{3}}\sqrt[3]{-1+\frac{2}{y}}
x=\sqrt[3]{-1+\frac{2}{y}}
x=e^{\frac{4\pi i}{3}}\sqrt[3]{-1+\frac{2}{y}}\text{, }y\neq 0
x uchun yechish
x=\sqrt[3]{-1+\frac{2}{y}}
y\neq 0
Grafik
Baham ko'rish
Klipbordga nusxa olish
2y^{-1}=x^{3}+1
Tenglamaning ikkala tarafini 2 ga ko'paytirish.
2\times \frac{1}{y}=x^{3}+1
Shartlarni qayta saralash.
2\times 1=yx^{3}+y
y qiymati 0 teng bo‘lmaydi, chunki nolga bo‘lish mumkin emas. Tenglamaning ikkala tarafini y ga ko'paytirish.
2=yx^{3}+y
2 hosil qilish uchun 2 va 1 ni ko'paytirish.
yx^{3}+y=2
Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.
\left(x^{3}+1\right)y=2
y'ga ega bo'lgan barcha shartlarni birlashtirish.
\frac{\left(x^{3}+1\right)y}{x^{3}+1}=\frac{2}{x^{3}+1}
Ikki tarafini x^{3}+1 ga bo‘ling.
y=\frac{2}{x^{3}+1}
x^{3}+1 ga bo'lish x^{3}+1 ga ko'paytirishni bekor qiladi.
y=\frac{2}{\left(x+1\right)\left(x^{2}-x+1\right)}
2 ni x^{3}+1 ga bo'lish.
y=\frac{2}{\left(x+1\right)\left(x^{2}-x+1\right)}\text{, }y\neq 0
y qiymati 0 teng bo‘lmaydi.
2y^{-1}=x^{3}+1
Tenglamaning ikkala tarafini 2 ga ko'paytirish.
2\times \frac{1}{y}=x^{3}+1
Shartlarni qayta saralash.
2\times 1=yx^{3}+y
y qiymati 0 teng bo‘lmaydi, chunki nolga bo‘lish mumkin emas. Tenglamaning ikkala tarafini y ga ko'paytirish.
2=yx^{3}+y
2 hosil qilish uchun 2 va 1 ni ko'paytirish.
yx^{3}+y=2
Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.
\left(x^{3}+1\right)y=2
y'ga ega bo'lgan barcha shartlarni birlashtirish.
\frac{\left(x^{3}+1\right)y}{x^{3}+1}=\frac{2}{x^{3}+1}
Ikki tarafini x^{3}+1 ga bo‘ling.
y=\frac{2}{x^{3}+1}
x^{3}+1 ga bo'lish x^{3}+1 ga ko'paytirishni bekor qiladi.
y=\frac{2}{\left(x+1\right)\left(x^{2}-x+1\right)}
2 ni x^{3}+1 ga bo'lish.
y=\frac{2}{\left(x+1\right)\left(x^{2}-x+1\right)}\text{, }y\neq 0
y qiymati 0 teng bo‘lmaydi.
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