x^2+1+6x^2+7x-2= eching

$${ x }^{ 2+1 } +6 { x }^{ 2 } +7x-2=$$

x ga nisbatan hosilani topish

$$3x^{2}+12x+7$$

Yig'indi uchun derivativ qoidasidan foydalanish qadamlari

3 olish uchun 2 va 1'ni qo'shing.

$$\frac{\mathrm{d}}{\mathrm{d}x}(x^{3}+6x^{2}+7x-2)$$

Polinomialning hosilasi bu uning shartlari hosilasining yig‘indisiga teng. Konstant shartning hosilasi 0. ax^{n} ning hosilasi nax^{n-1}.

$$3x^{3-1}+2\times 6x^{2-1}+7x^{1-1}$$

3 dan 1 ni ayirish.

$$3x^{2}+2\times 6x^{2-1}+7x^{1-1}$$

2 ni 6 marotabaga ko'paytirish.

$$3x^{2}+12x^{2-1}+7x^{1-1}$$

2 dan 1 ni ayirish.

$$3x^{2}+12x^{1}+7x^{1-1}$$

1 dan 1 ni ayirish.

$$3x^{2}+12x^{1}+7x^{0}$$

Har qanday t sharti uchun t^{1}=t.

$$3x^{2}+12x+7x^{0}$$

Har qanday t sharti uchun (0 bundan mustasno) t^{0}=1.

$$3x^{2}+12x+7\times 1$$

Har qanday t sharti uchun t\times 1=t va 1t=t.

$$3x^{2}+12x+7$$

Baholash

$$\left(x+2\right)\left(x^{2}+4x-1\right)$$

Yechim qadamlari

3 olish uchun 2 va 1'ni qo'shing.

$$x^{3}+6x^{2}+7x-2$$