x^2-9x-48=0 eching

$${ x }^{ 2 } -9x-48=0$$

x uchun yechish

$$x = \frac{\sqrt{273} + 9}{2} \approx 12,761355821$$

$$x=\frac{9-\sqrt{273}}{2}\approx -3,761355821$$

Kvadrat tenglamalaridan foydalanish qoidalari

ax^{2}+bx+c=0 shaklidagi barcha tenglamalarni kvadrat formulasi bilan yechish mumkin: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Kvadrat formula ikki yechmni taqdim qiladi, biri ± qo'shish bo'lganda, va ikkinchisi ayiruv bo'lganda.

$$x^{2}-9x-48=0$$

Ushbu tenglama standart shaklidadir: ax^{2}+bx+c=0. Kvadrat tenglama formulasida, \frac{-b±\sqrt{b^{2}-4ac}}{2a} 1 ni a, -9 ni b va -48 ni c bilan almashtiring.

$$x=\frac{-\left(-9\right)±\sqrt{\left(-9\right)^{2}-4\left(-48\right)}}{2}$$

-9 kvadratini chiqarish.

$$x=\frac{-\left(-9\right)±\sqrt{81-4\left(-48\right)}}{2}$$

-4 ni -48 marotabaga ko'paytirish.

$$x=\frac{-\left(-9\right)±\sqrt{81+192}}{2}$$

81 ni 192 ga qo'shish.

$$x=\frac{-\left(-9\right)±\sqrt{273}}{2}$$

-9 ning teskarisi 9 ga teng.

$$x=\frac{9±\sqrt{273}}{2}$$

x=\frac{9±\sqrt{273}}{2} tenglamasini yeching, bunda ± musbat. 9 ni \sqrt{273} ga qo'shish.

$$x=\frac{\sqrt{273}+9}{2}$$

x=\frac{9±\sqrt{273}}{2} tenglamasini yeching, bunda ± manfiy. 9 dan \sqrt{273} ni ayirish.

$$x=\frac{9-\sqrt{273}}{2}$$

Tenglama yechildi.

$$x=\frac{\sqrt{273}+9}{2} x=\frac{9-\sqrt{273}}{2}$$

Kvadratni yakunlash bo'yicha qadamlar

Bu kabi kvadrat tenglamalarni kvadratni yakunlab yechish mumkin. Kvadratni yechish uchun tenglama avval ushbu shaklda bo'lishi shart: x^{2}+bx=c.

$$x^{2}-9x-48=0$$

48 ni tenglamaning ikkala tarafiga qo'shish.

$$x^{2}-9x-48-\left(-48\right)=-\left(-48\right)$$

O‘zidan -48 ayirilsa 0 qoladi.

$$x^{2}-9x=-\left(-48\right)$$

0 dan -48 ni ayirish.

$$x^{2}-9x=48$$

-9 ni bo‘lish, x shartining koeffitsienti, 2 ga -\frac{9}{2} olish uchun. Keyin, -\frac{9}{2} ning kvadratini tenglamaning ikkala tarafiga qo‘shing. Ushbu qadam tenglamaning chap qismini mukammal kvadrat sifatida hosil qiladi.

$$x^{2}-9x+\left(-\frac{9}{2}\right)^{2}=48+\left(-\frac{9}{2}\right)^{2}$$

Kasrning ham suratini, ham maxrajini kvadratga ko'paytirib -\frac{9}{2} kvadratini chiqarish.

$$x^{2}-9x+\frac{81}{4}=48+\frac{81}{4}$$

48 ni \frac{81}{4} ga qo'shish.

$$x^{2}-9x+\frac{81}{4}=\frac{273}{4}$$

x^{2}-9x+\frac{81}{4} omili. Odatda, x^{2}+bx+c mukammal kvadrat bo'lsa, u doimo \left(x+\frac{b}{2}\right)^{2} omil sifatida bo'lishi mumkin.

$$\left(x-\frac{9}{2}\right)^{2}=\frac{273}{4}$$

Tenglamaning ikkala tarafining kvadrat ildizini chiqarish.

$$\sqrt{\left(x-\frac{9}{2}\right)^{2}}=\sqrt{\frac{273}{4}}$$

Qisqartirish.

$$x-\frac{9}{2}=\frac{\sqrt{273}}{2} x-\frac{9}{2}=-\frac{\sqrt{273}}{2}$$

\frac{9}{2} ni tenglamaning ikkala tarafiga qo'shish.

$$x=\frac{\sqrt{273}+9}{2} x=\frac{9-\sqrt{273}}{2}$$