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x^{2}-5000002x+10=0
Kvadrat koʻp tenglama bu orqali hisoblanadi: ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), bu yerda x_{1} va x_{2} ax^{2}+bx+c=0 kvadrat tenglamaning yechimlari.
x=\frac{-\left(-5000002\right)±\sqrt{\left(-5000002\right)^{2}-4\times 10}}{2}
ax^{2}+bx+c=0 shaklidagi barcha tenglamalarni kvadrat formulasi bilan yechish mumkin: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Kvadrat formula ikki yechmni taqdim qiladi, biri ± qo'shish bo'lganda, va ikkinchisi ayiruv bo'lganda.
x=\frac{-\left(-5000002\right)±\sqrt{25000020000004-4\times 10}}{2}
-5000002 kvadratini chiqarish.
x=\frac{-\left(-5000002\right)±\sqrt{25000020000004-40}}{2}
-4 ni 10 marotabaga ko'paytirish.
x=\frac{-\left(-5000002\right)±\sqrt{25000019999964}}{2}
25000020000004 ni -40 ga qo'shish.
x=\frac{-\left(-5000002\right)±6\sqrt{694444999999}}{2}
25000019999964 ning kvadrat ildizini chiqarish.
x=\frac{5000002±6\sqrt{694444999999}}{2}
-5000002 ning teskarisi 5000002 ga teng.
x=\frac{6\sqrt{694444999999}+5000002}{2}
x=\frac{5000002±6\sqrt{694444999999}}{2} tenglamasini yeching, bunda ± musbat. 5000002 ni 6\sqrt{694444999999} ga qo'shish.
x=3\sqrt{694444999999}+2500001
5000002+6\sqrt{694444999999} ni 2 ga bo'lish.
x=\frac{5000002-6\sqrt{694444999999}}{2}
x=\frac{5000002±6\sqrt{694444999999}}{2} tenglamasini yeching, bunda ± manfiy. 5000002 dan 6\sqrt{694444999999} ni ayirish.
x=2500001-3\sqrt{694444999999}
5000002-6\sqrt{694444999999} ni 2 ga bo'lish.
x^{2}-5000002x+10=\left(x-\left(3\sqrt{694444999999}+2500001\right)\right)\left(x-\left(2500001-3\sqrt{694444999999}\right)\right)
ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right) formulasi yordamida amalni hisoblang. x_{1} uchun 2500001+3\sqrt{694444999999} ga va x_{2} uchun 2500001-3\sqrt{694444999999} ga bo‘ling.