x^2-12+32=0 eching

$${ x }^{ 2 } -12+32=0$$

x uchun yechish (complex solution)

$$x=-2\sqrt{5}i\approx -0-4,472135955i$$

$$x=2\sqrt{5}i\approx 4,472135955i$$

Kvadrat ildizini topish bo'yicha qadamlar

20 olish uchun -12 va 32'ni qo'shing.

$$x^{2}+20=0$$

Ikkala tarafdan 20 ni ayirish. Har qanday sonni noldan ayirsangiz, o‘zining manfiyi chiqadi.

$$x^{2}=-20$$

Tenglama yechildi.

$$x=2\sqrt{5}i x=-2\sqrt{5}i$$

Kvadrat tenglamalaridan foydalanish qoidalari

20 olish uchun -12 va 32'ni qo'shing.

$$x^{2}+20=0$$

Ushbu tenglama standart shaklidadir: ax^{2}+bx+c=0. Kvadrat tenglama formulasida, \frac{-b±\sqrt{b^{2}-4ac}}{2a} 1 ni a, 0 ni b va 20 ni c bilan almashtiring.

$$x=\frac{0±\sqrt{0^{2}-4\times 20}}{2}$$

0 kvadratini chiqarish.

$$x=\frac{0±\sqrt{-4\times 20}}{2}$$

-4 ni 20 marotabaga ko'paytirish.

$$x=\frac{0±\sqrt{-80}}{2}$$

-80 ning kvadrat ildizini chiqarish.

$$x=\frac{0±4\sqrt{5}i}{2}$$

x=\frac{0±4\sqrt{5}i}{2} tenglamasini yeching, bunda ± musbat.

$$x=2\sqrt{5}i$$

x=\frac{0±4\sqrt{5}i}{2} tenglamasini yeching, bunda ± manfiy.

$$x=-2\sqrt{5}i$$

Tenglama yechildi.

$$x=2\sqrt{5}i x=-2\sqrt{5}i$$