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x^{2}-115x+4254=0
ax^{2}+bx+c=0 shaklidagi barcha tenglamalarni kvadrat formulasi bilan yechish mumkin: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Kvadrat formula ikki yechmni taqdim qiladi, biri ± qo'shish bo'lganda, va ikkinchisi ayiruv bo'lganda.
x=\frac{-\left(-115\right)±\sqrt{\left(-115\right)^{2}-4\times 4254}}{2}
Ushbu tenglama standart shaklidadir: ax^{2}+bx+c=0. Kvadrat tenglama formulasida, \frac{-b±\sqrt{b^{2}-4ac}}{2a} 1 ni a, -115 ni b va 4254 ni c bilan almashtiring.
x=\frac{-\left(-115\right)±\sqrt{13225-4\times 4254}}{2}
-115 kvadratini chiqarish.
x=\frac{-\left(-115\right)±\sqrt{13225-17016}}{2}
-4 ni 4254 marotabaga ko'paytirish.
x=\frac{-\left(-115\right)±\sqrt{-3791}}{2}
13225 ni -17016 ga qo'shish.
x=\frac{-\left(-115\right)±\sqrt{3791}i}{2}
-3791 ning kvadrat ildizini chiqarish.
x=\frac{115±\sqrt{3791}i}{2}
-115 ning teskarisi 115 ga teng.
x=\frac{115+\sqrt{3791}i}{2}
x=\frac{115±\sqrt{3791}i}{2} tenglamasini yeching, bunda ± musbat. 115 ni i\sqrt{3791} ga qo'shish.
x=\frac{-\sqrt{3791}i+115}{2}
x=\frac{115±\sqrt{3791}i}{2} tenglamasini yeching, bunda ± manfiy. 115 dan i\sqrt{3791} ni ayirish.
x=\frac{115+\sqrt{3791}i}{2} x=\frac{-\sqrt{3791}i+115}{2}
Tenglama yechildi.
x^{2}-115x+4254=0
Bu kabi kvadrat tenglamalarni kvadratni yakunlab yechish mumkin. Kvadratni yechish uchun tenglama avval ushbu shaklda bo'lishi shart: x^{2}+bx=c.
x^{2}-115x+4254-4254=-4254
Tenglamaning ikkala tarafidan 4254 ni ayirish.
x^{2}-115x=-4254
O‘zidan 4254 ayirilsa 0 qoladi.
x^{2}-115x+\left(-\frac{115}{2}\right)^{2}=-4254+\left(-\frac{115}{2}\right)^{2}
-115 ni bo‘lish, x shartining koeffitsienti, 2 ga -\frac{115}{2} olish uchun. Keyin, -\frac{115}{2} ning kvadratini tenglamaning ikkala tarafiga qo‘shing. Ushbu qadam tenglamaning chap qismini mukammal kvadrat sifatida hosil qiladi.
x^{2}-115x+\frac{13225}{4}=-4254+\frac{13225}{4}
Kasrning ham suratini, ham maxrajini kvadratga ko'paytirib -\frac{115}{2} kvadratini chiqarish.
x^{2}-115x+\frac{13225}{4}=-\frac{3791}{4}
-4254 ni \frac{13225}{4} ga qo'shish.
\left(x-\frac{115}{2}\right)^{2}=-\frac{3791}{4}
x^{2}-115x+\frac{13225}{4} omili. Odatda, x^{2}+bx+c mukammal kvadrat bo'lsa, u doimo \left(x+\frac{b}{2}\right)^{2} omil sifatida bo'lishi mumkin.
\sqrt{\left(x-\frac{115}{2}\right)^{2}}=\sqrt{-\frac{3791}{4}}
Tenglamaning ikkala tarafining kvadrat ildizini chiqarish.
x-\frac{115}{2}=\frac{\sqrt{3791}i}{2} x-\frac{115}{2}=-\frac{\sqrt{3791}i}{2}
Qisqartirish.
x=\frac{115+\sqrt{3791}i}{2} x=\frac{-\sqrt{3791}i+115}{2}
\frac{115}{2} ni tenglamaning ikkala tarafiga qo'shish.