x^2-10+18=0 eching

$${ x }^{ 2 } -10+18=0$$

x uchun yechish (complex solution)

$$x=-2\sqrt{2}i\approx -0-2,828427125i$$

$$x=2\sqrt{2}i\approx 2,828427125i$$

Kvadrat ildizini topish bo'yicha qadamlar

8 olish uchun -10 va 18'ni qo'shing.

$$x^{2}+8=0$$

Ikkala tarafdan 8 ni ayirish. Har qanday sonni noldan ayirsangiz, o‘zining manfiyi chiqadi.

$$x^{2}=-8$$

Tenglama yechildi.

$$x=2\sqrt{2}i x=-2\sqrt{2}i$$

Kvadrat tenglamalaridan foydalanish qoidalari

8 olish uchun -10 va 18'ni qo'shing.

$$x^{2}+8=0$$

Ushbu tenglama standart shaklidadir: ax^{2}+bx+c=0. Kvadrat tenglama formulasida, \frac{-b±\sqrt{b^{2}-4ac}}{2a} 1 ni a, 0 ni b va 8 ni c bilan almashtiring.

$$x=\frac{0±\sqrt{0^{2}-4\times 8}}{2}$$

0 kvadratini chiqarish.

$$x=\frac{0±\sqrt{-4\times 8}}{2}$$

-4 ni 8 marotabaga ko'paytirish.

$$x=\frac{0±\sqrt{-32}}{2}$$

-32 ning kvadrat ildizini chiqarish.

$$x=\frac{0±4\sqrt{2}i}{2}$$

x=\frac{0±4\sqrt{2}i}{2} tenglamasini yeching, bunda ± musbat.

$$x=2\sqrt{2}i$$

x=\frac{0±4\sqrt{2}i}{2} tenglamasini yeching, bunda ± manfiy.

$$x=-2\sqrt{2}i$$

Tenglama yechildi.

$$x=2\sqrt{2}i x=-2\sqrt{2}i$$