x^2-24^2+8=0 eching

$${ x }^{ 2 } - { 24 }^{ 2 } +8 = 0$$

x uchun yechish

$$x=2\sqrt{142}\approx 23,832750576$$

$$x=-2\sqrt{142}\approx -23,832750576$$

Kvadrat ildizini topish bo'yicha qadamlar

2 daraja ko‘rsatkichini 24 ga hisoblang va 576 ni qiymatni oling.

$$x^{2}-576+8=0$$

-568 olish uchun -576 va 8'ni qo'shing.

$$x^{2}-568=0$$

568 ni ikki tarafga qo’shing. Har qanday songa nolni qo‘shsangiz, o‘zi chiqadi.

$$x^{2}=568$$

Tenglamaning ikkala tarafining kvadrat ildizini chiqarish.

$$x=2\sqrt{142} x=-2\sqrt{142}$$

Kvadrat tenglamalaridan foydalanish qoidalari

2 daraja ko‘rsatkichini 24 ga hisoblang va 576 ni qiymatni oling.

$$x^{2}-576+8=0$$

-568 olish uchun -576 va 8'ni qo'shing.

$$x^{2}-568=0$$

Ushbu tenglama standart shaklidadir: ax^{2}+bx+c=0. Kvadrat tenglama formulasida, \frac{-b±\sqrt{b^{2}-4ac}}{2a} 1 ni a, 0 ni b va -568 ni c bilan almashtiring.

$$x=\frac{0±\sqrt{0^{2}-4\left(-568\right)}}{2}$$

0 kvadratini chiqarish.

$$x=\frac{0±\sqrt{-4\left(-568\right)}}{2}$$

-4 ni -568 marotabaga ko'paytirish.

$$x=\frac{0±\sqrt{2272}}{2}$$

2272 ning kvadrat ildizini chiqarish.

$$x=\frac{0±4\sqrt{142}}{2}$$

x=\frac{0±4\sqrt{142}}{2} tenglamasini yeching, bunda ± musbat.

$$x=2\sqrt{142}$$

x=\frac{0±4\sqrt{142}}{2} tenglamasini yeching, bunda ± manfiy.

$$x=-2\sqrt{142}$$

Tenglama yechildi.

$$x=2\sqrt{142} x=-2\sqrt{142}$$