x^2=left(x-12right)^2 eching

$${ x }^{ 2 } = { \left(x-12 \right) }^{ 2 }$$

x uchun yechish

$$x=6$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

\left(a-b\right)^{2}=a^{2}-2ab+b^{2} binom teoremasini \left(x-12\right)^{2} kengaytirilishi uchun ishlating.

$$x^{2}=x^{2}-24x+144$$

Ikkala tarafdan x^{2} ni ayirish.

$$x^{2}-x^{2}=-24x+144$$

0 ni olish uchun x^{2} va -x^{2} ni birlashtirish.

$$0=-24x+144$$

Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.

$$-24x+144=0$$

Ikkala tarafdan 144 ni ayirish. Har qanday sonni noldan ayirsangiz, o‘zining manfiyi chiqadi.

$$-24x=-144$$

Ikki tarafini -24 ga bo‘ling.

$$x=\frac{-144}{-24}$$

6 ni olish uchun -144 ni -24 ga bo‘ling.

$$x=6$$