x^2=pi eching

$${ x }^{ 2 } = \pi$$

x uchun yechish

$$x=\sqrt{\pi }\approx 1,772453851$$

$$x=-\sqrt{\pi }\approx -1,772453851$$

Kvadrat ildizini topish bo'yicha qadamlar

Tenglamaning ikkala tarafining kvadrat ildizini chiqarish.

$$x=\sqrt{\pi } x=-\sqrt{\pi }$$

Kvadrat tenglamalaridan foydalanish qoidalari

Bu kabi kvadrat tenglamalarni x^{2} sharti bilan, biroq x shartisiz hamon kvadrat tenglamasidan foydalanib yechish mumkin, \frac{-b±\sqrt{b^{2}-4ac}}{2a}, ular standart formulaga solingandan so'ng: ax^{2}+bx+c=0.

$$x^{2}=\pi$$

Tenglamaning ikkala tarafidan \pi ni ayirish.

$$x^{2}-\pi =\pi -\pi$$

O‘zidan \pi ayirilsa 0 qoladi.

$$x^{2}-\pi =0$$

Ushbu tenglama standart shaklidadir: ax^{2}+bx+c=0. Kvadrat tenglama formulasida, \frac{-b±\sqrt{b^{2}-4ac}}{2a} 1 ni a, 0 ni b va -\pi ni c bilan almashtiring.

$$x=\frac{0±\sqrt{0^{2}-4\left(-\pi \right)}}{2}$$

0 kvadratini chiqarish.

$$x=\frac{0±\sqrt{-4\left(-\pi \right)}}{2}$$

-4 ni -\pi marotabaga ko'paytirish.

$$x=\frac{0±\sqrt{4\pi }}{2}$$

4\pi ning kvadrat ildizini chiqarish.

$$x=\frac{0±2\sqrt{\pi }}{2}$$

x=\frac{0±2\sqrt{\pi }}{2} tenglamasini yeching, bunda ± musbat.

$$x=\sqrt{\pi }$$

x=\frac{0±2\sqrt{\pi }}{2} tenglamasini yeching, bunda ± manfiy.

$$x=-\sqrt{\pi }$$

Tenglama yechildi.

$$x=\sqrt{\pi } x=-\sqrt{\pi }$$