x^2+bx+7=0 eching

$${ x }^{ 2 } +bx+7 = 0$$

b uchun yechish

$$b=-x-\frac{7}{x}$$

$$x\neq 0$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

Ikkala tarafdan x^{2} ni ayirish. Har qanday sonni noldan ayirsangiz, o‘zining manfiyi chiqadi.

$$bx+7=-x^{2}$$

Ikkala tarafdan 7 ni ayirish.

$$bx=-x^{2}-7$$

Tenglama standart shaklda.

$$xb=-x^{2}-7$$

Ikki tarafini x ga bo‘ling.

$$\frac{xb}{x}=\frac{-x^{2}-7}{x}$$

x ga bo'lish x ga ko'paytirishni bekor qiladi.

$$b=\frac{-x^{2}-7}{x}$$

-x^{2}-7 ni x ga bo'lish.

$$b=-x-\frac{7}{x}$$

x uchun yechish (complex solution)

$$x=\frac{\sqrt{b^{2}-28}-b}{2}$$

$$x=\frac{-\sqrt{b^{2}-28}-b}{2}$$

x uchun yechish

$$x=\frac{\sqrt{b^{2}-28}-b}{2}$$

$$x=\frac{-\sqrt{b^{2}-28}-b}{2}\text{, }|b|\geq 2\sqrt{7}$$