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x^{2}+985565x+2=0
ax^{2}+bx+c=0 shaklidagi barcha tenglamalarni kvadrat formulasi bilan yechish mumkin: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Kvadrat formula ikki yechmni taqdim qiladi, biri ± qo'shish bo'lganda, va ikkinchisi ayiruv bo'lganda.
x=\frac{-985565±\sqrt{985565^{2}-4\times 2}}{2}
Ushbu tenglama standart shaklidadir: ax^{2}+bx+c=0. Kvadrat tenglama formulasida, \frac{-b±\sqrt{b^{2}-4ac}}{2a} 1 ni a, 985565 ni b va 2 ni c bilan almashtiring.
x=\frac{-985565±\sqrt{971338369225-4\times 2}}{2}
985565 kvadratini chiqarish.
x=\frac{-985565±\sqrt{971338369225-8}}{2}
-4 ni 2 marotabaga ko'paytirish.
x=\frac{-985565±\sqrt{971338369217}}{2}
971338369225 ni -8 ga qo'shish.
x=\frac{\sqrt{971338369217}-985565}{2}
x=\frac{-985565±\sqrt{971338369217}}{2} tenglamasini yeching, bunda ± musbat. -985565 ni \sqrt{971338369217} ga qo'shish.
x=\frac{-\sqrt{971338369217}-985565}{2}
x=\frac{-985565±\sqrt{971338369217}}{2} tenglamasini yeching, bunda ± manfiy. -985565 dan \sqrt{971338369217} ni ayirish.
x=\frac{\sqrt{971338369217}-985565}{2} x=\frac{-\sqrt{971338369217}-985565}{2}
Tenglama yechildi.
x^{2}+985565x+2=0
Bu kabi kvadrat tenglamalarni kvadratni yakunlab yechish mumkin. Kvadratni yechish uchun tenglama avval ushbu shaklda bo'lishi shart: x^{2}+bx=c.
x^{2}+985565x+2-2=-2
Tenglamaning ikkala tarafidan 2 ni ayirish.
x^{2}+985565x=-2
O‘zidan 2 ayirilsa 0 qoladi.
x^{2}+985565x+\left(\frac{985565}{2}\right)^{2}=-2+\left(\frac{985565}{2}\right)^{2}
985565 ni bo‘lish, x shartining koeffitsienti, 2 ga \frac{985565}{2} olish uchun. Keyin, \frac{985565}{2} ning kvadratini tenglamaning ikkala tarafiga qo‘shing. Ushbu qadam tenglamaning chap qismini mukammal kvadrat sifatida hosil qiladi.
x^{2}+985565x+\frac{971338369225}{4}=-2+\frac{971338369225}{4}
Kasrning ham suratini, ham maxrajini kvadratga ko'paytirib \frac{985565}{2} kvadratini chiqarish.
x^{2}+985565x+\frac{971338369225}{4}=\frac{971338369217}{4}
-2 ni \frac{971338369225}{4} ga qo'shish.
\left(x+\frac{985565}{2}\right)^{2}=\frac{971338369217}{4}
x^{2}+985565x+\frac{971338369225}{4} omili. Odatda, x^{2}+bx+c mukammal kvadrat bo'lsa, u doimo \left(x+\frac{b}{2}\right)^{2} omil sifatida bo'lishi mumkin.
\sqrt{\left(x+\frac{985565}{2}\right)^{2}}=\sqrt{\frac{971338369217}{4}}
Tenglamaning ikkala tarafining kvadrat ildizini chiqarish.
x+\frac{985565}{2}=\frac{\sqrt{971338369217}}{2} x+\frac{985565}{2}=-\frac{\sqrt{971338369217}}{2}
Qisqartirish.
x=\frac{\sqrt{971338369217}-985565}{2} x=\frac{-\sqrt{971338369217}-985565}{2}
Tenglamaning ikkala tarafidan \frac{985565}{2} ni ayirish.