x^2+8=75 eching

$${ x }^{ 2 } +8=75$$

x uchun yechish

$$x=\sqrt{67}\approx 8,185352772$$

$$x=-\sqrt{67}\approx -8,185352772$$

Kvadrat ildizini topish bo'yicha qadamlar

Ikkala tarafdan 8 ni ayirish.

$$x^{2}=75-8$$

67 olish uchun 75 dan 8 ni ayirish.

$$x^{2}=67$$

Tenglamaning ikkala tarafining kvadrat ildizini chiqarish.

$$x=\sqrt{67} x=-\sqrt{67}$$

Kvadrat tenglamalaridan foydalanish qoidalari

Ikkala tarafdan 75 ni ayirish.

$$x^{2}+8-75=0$$

-67 olish uchun 8 dan 75 ni ayirish.

$$x^{2}-67=0$$

Ushbu tenglama standart shaklidadir: ax^{2}+bx+c=0. Kvadrat tenglama formulasida, \frac{-b±\sqrt{b^{2}-4ac}}{2a} 1 ni a, 0 ni b va -67 ni c bilan almashtiring.

$$x=\frac{0±\sqrt{0^{2}-4\left(-67\right)}}{2}$$

0 kvadratini chiqarish.

$$x=\frac{0±\sqrt{-4\left(-67\right)}}{2}$$

-4 ni -67 marotabaga ko'paytirish.

$$x=\frac{0±\sqrt{268}}{2}$$

268 ning kvadrat ildizini chiqarish.

$$x=\frac{0±2\sqrt{67}}{2}$$

x=\frac{0±2\sqrt{67}}{2} tenglamasini yeching, bunda ± musbat.

$$x=\sqrt{67}$$

x=\frac{0±2\sqrt{67}}{2} tenglamasini yeching, bunda ± manfiy.

$$x=-\sqrt{67}$$

Tenglama yechildi.

$$x=\sqrt{67} x=-\sqrt{67}$$