x^2+7x+5 eching

$${ x }^{ 2 } +7x+5$$

Omil

$$\left(x-\frac{-\sqrt{29}-7}{2}\right)\left(x-\frac{\sqrt{29}-7}{2}\right)$$

Kvadrat tenglamalaridan foydalanish qoidalari

Kvadrat koʻp tenglama bu orqali hisoblanadi: ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), bu yerda x_{1} va x_{2} ax^{2}+bx+c=0 kvadrat tenglamaning yechimlari.

$$x^{2}+7x+5=0$$

ax^{2}+bx+c=0 shaklidagi barcha tenglamalarni kvadrat formulasi bilan yechish mumkin: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Kvadrat formula ikki yechmni taqdim qiladi, biri ± qo'shish bo'lganda, va ikkinchisi ayiruv bo'lganda.

$$x=\frac{-7±\sqrt{7^{2}-4\times 5}}{2}$$

7 kvadratini chiqarish.

$$x=\frac{-7±\sqrt{49-4\times 5}}{2}$$

-4 ni 5 marotabaga ko'paytirish.

$$x=\frac{-7±\sqrt{49-20}}{2}$$

49 ni -20 ga qo'shish.

$$x=\frac{-7±\sqrt{29}}{2}$$

x=\frac{-7±\sqrt{29}}{2} tenglamasini yeching, bunda ± musbat. -7 ni \sqrt{29} ga qo'shish.

$$x=\frac{\sqrt{29}-7}{2}$$

x=\frac{-7±\sqrt{29}}{2} tenglamasini yeching, bunda ± manfiy. -7 dan \sqrt{29} ni ayirish.

$$x=\frac{-\sqrt{29}-7}{2}$$

ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right) formulasi yordamida amalni hisoblang. x_{1} uchun \frac{-7+\sqrt{29}}{2} ga va x_{2} uchun \frac{-7-\sqrt{29}}{2} ga bo‘ling.

$$x^{2}+7x+5=\left(x-\frac{\sqrt{29}-7}{2}\right)\left(x-\frac{-\sqrt{29}-7}{2}\right)$$

Baholash

$$x^{2}+7x+5$$