x^2+6=54 eching

$${ x }^{ 2 } +6 = 54$$

x uchun yechish

$$x=4\sqrt{3}\approx 6,92820323$$

$$x=-4\sqrt{3}\approx -6,92820323$$

Kvadrat ildizini topish bo'yicha qadamlar

Ikkala tarafdan 6 ni ayirish.

$$x^{2}=54-6$$

48 olish uchun 54 dan 6 ni ayirish.

$$x^{2}=48$$

Tenglamaning ikkala tarafining kvadrat ildizini chiqarish.

$$x=4\sqrt{3} x=-4\sqrt{3}$$

Kvadrat tenglamalaridan foydalanish qoidalari

Ikkala tarafdan 54 ni ayirish.

$$x^{2}+6-54=0$$

-48 olish uchun 6 dan 54 ni ayirish.

$$x^{2}-48=0$$

Ushbu tenglama standart shaklidadir: ax^{2}+bx+c=0. Kvadrat tenglama formulasida, \frac{-b±\sqrt{b^{2}-4ac}}{2a} 1 ni a, 0 ni b va -48 ni c bilan almashtiring.

$$x=\frac{0±\sqrt{0^{2}-4\left(-48\right)}}{2}$$

0 kvadratini chiqarish.

$$x=\frac{0±\sqrt{-4\left(-48\right)}}{2}$$

-4 ni -48 marotabaga ko'paytirish.

$$x=\frac{0±\sqrt{192}}{2}$$

192 ning kvadrat ildizini chiqarish.

$$x=\frac{0±8\sqrt{3}}{2}$$

x=\frac{0±8\sqrt{3}}{2} tenglamasini yeching, bunda ± musbat.

$$x=4\sqrt{3}$$

x=\frac{0±8\sqrt{3}}{2} tenglamasini yeching, bunda ± manfiy.

$$x=-4\sqrt{3}$$

Tenglama yechildi.

$$x=4\sqrt{3} x=-4\sqrt{3}$$